Let g(x)=2x and h(x)=x^2+4. evaluate (h o g)(-2)

Mathematics

1 answer:

Kamila [148]4 years ago

3 0

G(-2) = 2*-2 = -4

(h o g)(-2) = (-4)^2 + 4 = 20 answer

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Answer:

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Step-by-step explanation:

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$\boxed{\sf \ \ f^{-1}(x)=\dfrac{x-6}{3} \ \ }$

Step-by-step explanation:

hello,

we can write

$fof^{-1}(x)=x \ and \ fof^{-1}(x)=f(f^{-1}(x))=3f^{-1}(x)+6 \ so\\3f^{-1}(x)+6=x \ \ subtract \ 6\\3f^{-1}(x)=x-6 \ \ divide \ \ by \ \ 3\\ f^{-1}(x)=\dfrac{x-6}{3}$