Answer:
39 athletes
Step-by-step explanation:
There is a total of 45 people on the bus. This INCLUDES the athletes (A), 2 coaches and 4 managers.
Therefore, we need to sum A, 2 and 4 and equal it to 45:
2 + 4 + A = 45 so we need to used equation d.
To calculate how many athletes are on the bus, find the value of A:
2 + 4 + A = 45
Subtract 2 from both sides: 4 + A = 43
Subtract 4 from both sides: A = 39
Clearly, wether we're talking about tiles, plants, pages, e-mails, friend or files, the math won't change! :)
Percentages are just special fractions, since they have denominator 100. So, for example, 64% of 75 is given by

So, you divide the number by 100 and then you multiply by the percentage you want. As a last example, 20% of 70 is

And so on with all the others
Answer:
2, 3, 4, 5, 6, 7 or 8.
Step-by-step explanation:
We know that the sum of two sides on a triangle should ALWAYS be greater than the third side. Then we have:
5-4 < x < 5 + 4
1 < x < 9
Therefore, the lenght of the third side could be any number between 1 and 9. If the lenght of the third side is an integrer, then the lenght could be:
2, 3, 4, 5, 6, 7 or 8.
Answer:
<h2>C</h2>
Step-by-step explanation:
Following the Pythagoras theorem
SohCahToa
meaning Soh - sine , opposite , hypotenuse
Cah - cos , adjacent , hypotenuse
Toa - tan , opposite ,adjacent
so , therefore sin B is correct,
- tan B is also correct,
- cos B is incorrect , the correct answer suppose to be 6/10
- cos C is correct ,
Hope this is helpful,
Have a nice day . :-)

nothing to it, is just a matter of solving for the derivative, which is already there