Answer:
0.0137
Step-by-step explanation:
Let X be the random variable that measures the number of incoming calls every ten minutes.
If the incoming calls to the system are Poisson distributed with a mean equal to 5 every 10 minutes, then the probability that there are k incoming calls in 10 minutes is

If the phone-answering system is capable of handling ten calls every 10 minutes, we want to find
P(X>10), or the equivalent 1 - P(X≤ 10).
But
1 - P(X≤ 10)= 1 -(P(X=0)+P(X=1)+...+P(X=10)) =

So, the probability that in a 10-minute period more calls will arrive than the system can handle is 0.0137
<u>Part</u><u> </u><u>(</u><u>i</u><u>)</u>
1) AB is perpendicular to BC, ED is perpendicular to CD, BC = CD (given)
2) Angles ABC and CDE are right angles (perpendicular lines form right angles)
3) Angles ABC and CDE are equal (all right angles are equal)
4) Angles ACB and DCE are equal (vertical angles are equal)
5) Triangles ABC and EDC are congruent (ASA)
<u>Part</u><u> </u><u>(</u><u>ii</u><u>)</u>
6) AB = DE (corresponding parts of congruent triangles are equal)
Answer:
just mutiply and then add all of it up
Step-by-step explanation:
Step-by-step explanation:
given,
MP = x - 8
PN = 3x - 9
MN = 21
we know,
according to segment addition postulate AB + BC = AC
now,
MP + PN = MN
→ x - 8 + 3x - 9 = 21
→ 4x - 17 = 21
→ 4x = 21 + 17
→ 4x = 38
→ x = 38/4 = 9
→ x = 9
therefore, value of x is 9.
hope this answer helps you dear! take care
Answer: the many shall not be televised
Step-by-step explanation: