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The area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units
<h3>Determining the perimeter and area of the triangle giving line equation</h3>In order to determine the area and perimeter of the lines, we will plot the giving lines, determine the point of intersection and then use the Pythagoras theorem to determine the dimension of the right triangle.
The points of intersection of the line are;
(x₁, y₁) = (- 0.4, 5.2),
(x₂, y₂) = (-0.8, 4.4),
(x₃, y₃) = (0, 4)
Determine the base
b² = c² -a²
b = √(-0.8)² + (4 - 4.4)²
b = 2√5 / 5
Determine the height
h = √((- 0.4) - (- 0.8))² + (5.2 - 4.4)²
height = 2√5 / 5
For the hypotenuse
r = √2 · b
r = 2√10 / 5
<h3>Determine the Perimeter and area</h3>Perimeter = s1+s2+s3
Perimeter = 2√5 / 5 + 2√5 / 5 + 2√10 / 5
Perimeter = (2√10 + 4√5) / 5 units
<u>For the area</u>
area = 1/2* base * height
A = 0.5 · (2√5 / 5) · (2√5 / 5)
A = 2/5 square units
Hence the area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units
Learn more on area and perimeter of triangles here: brainly.com/question/12010318
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Answer:
Step-by-step explanation:
As the mean is 20.2 and the standard deviation is 2.4
The range within the first standard deviation is
(17.8,22.6)
This means that we can safely use the range of (18,22) as we cannot confirm whether the other values fall within the range.
Within this range there are