Answer:
%P = 8%
the percentage of fat in the mixture is 8%
Step-by-step explanation:
Given;
The percentage of fat in the mixture is;
%P = total mass of fat in mixture/total mass of mixture × 100%
%P = F/T × 100% ….....1
Mass of fat in mixture is;
She purchases 5 pounds of ground beef which is 15% fat
F1 = 15% of 5 pounds = 0.15×5 pounds
F1 = 0.75 pound
and combines it with 7 pounds of ground turkey which is only 3% fat
F2 = 3% of 7 pounds = 0.03 × 7
F2 = 0.21 pound
Total mass F = F1 + F2
F = 0.75+0.21
F = 0.96 pound
Total mass of mixture T = 5 + 7 pounds
T = 12 pounds.
From equation 1,
%P = F/T × 100%
%P = 0.96/12 × 100%
%P = 0.08×100%
%P = 8%
the percentage of fat in the mixture is 8%
PV = nRT
P: pressure of gas
V: volume of gas
n: number of moles of gases
R: constant
T: thermodynamic temperature of gas
All the statements apply
Hope it helped!
we know that
total of sum of arc is 360
so, sum of both arc must be 360
so, we get

now, we can solve for x

............Answer
B. is the answer hope I got it right: )
<em>Answer:</em>
<em>r = -</em>
<em />
<em>Step-by-step explanation:</em>
<em>Rewrite the equation as </em>
<em> = m</em>
<em>Remove the radical on the left side of the equation by squaring both sides of the equation.</em>
<em>(</em>
<em> = m^2</em>
<em>Then, you simplify each of the equation. </em>
<em>Rewrite: (</em>
<em> as </em>
<em />
<em>Remove any parentheses if needed.</em>
<em>Solve for r. </em>
<em>Multiply each term by r and simplify."</em>
<em>Multiply both sides of the equation by 5.</em>
<em>6a+r= m^2r⋅(5)</em>
<em>Remove parentheses.</em>
<em>Move 5 to the left of (m
^2) r
</em>
<em>6a+r=5m^2)r</em>
<em>Subtract 5m^2)r from both sides of the equation.</em>
<em>6a+r-5m^2)r=0</em>
<em>Subtract 6a from both sides of the equation.</em>
<em>r-5m^2)r=-6a</em>
<em>Factor r out of r-5m^2)r </em>
<em>r(1-5m^2)=-6a</em>
Divide each term by 1-5m^2 and simplify.
r = - 
There you go, hope this helps!