The answer to your question is 8.9
Answer: See you have to understand the problem and then solve it Answer is: 5g - 2/10
T=2π/|b|. The period of an equation of the form y = a sin bx is T=2π/|b|.
In mathematics the curve that graphically represents the sine function and also that function itself is called sinusoid or sinusoid. It is a curve that describes a repetitive and smooth oscillation. It can be represented as y(x) = a sin (ωx+φ) where a is the amplitude, ω is the angular velocity with ω=2πf, (ωx+φ) is the oscillation phase, and φ the initial phase.
The period T of the sin function is T=1/f, from the equation ω=2πf we can clear f and substitute in T=1/f.
f=ω/2π
Substituting in T=1/f:
T=1/ω/2π -------> T = 2π/ω
For the example y = a sin bx, we have that a is the amplitude, b is ω and the initial phase φ = 0. So, we have that the period T of the function a sin bx is:
T=2π/|b|
Answer:
Step-by-step explanation:
First, subtract 50.45x from both sides. Then divide by 7.5 on both sides.
Answer:
1. 10
2. 5
3. 10
4. 8
Step-by-step explanation:
1. 8²+6² = 100
The square root of 100 = 10
2. 3²+4² = 25
The square root of 25 = 5
3. 26²-24²=100
The square root of 100 = 10
4. 10²-6² = 64
The square root of 64 = 8
