Answer:
10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
In this question, we are tasked with writing the product as a sum.
To do this, we shall be using the sum to product formula below;
cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]
From the question, we can say α= 5x and β= 10x
Plugging these values into the equation, we have
10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]
= 5[sin (15x) - sin (-5x)]
We apply odd identity i.e sin(-x) = -sinx
Thus applying same to sin(-5x)
sin(-5x) = -sin(5x)
Thus;
5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]
= 5[sin (15x) + sin (5x)]
Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
Answer:
E' (-2,5)
F' (-3,1)
G' (-2,-1)
H' (0,3)
Step-by-step explanation:
The rule for 90 degree clockwise rotation is (h,k) -> (k,-h). This means flip the x-value's sign and then switch x and y's position. For example E (-5,-2), first flip x's sign (5,-2) and then switch x and y's places (-2,5).
8. You just multiply x and y together
