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kenny6666 [7]
3 years ago
10

Everyday,Tobys burrito stand uses 3 bags of tortillas, for how many days will2/3 of a bag of tortillas last​

Mathematics
2 answers:
Ulleksa [173]3 years ago
8 0
Set up a ratio.
3 bags/1 day = 2/3 bag/x day
Cross multiply to solve.
3x=2/3
So x=2/3(1/3)=2/9 of a day
Anettt [7]3 years ago
3 0

Answer : The number of days will 2/3 of a bag of tortillas last​ is, \frac{2}{9} days.

Step-by-step explanation :

As we are given that the Tobys burrito stand uses 3 bags of tortillas in 1 day.

Now we have to determine the number of days will 2/3 of a bag of tortillas last​.

As, Tobys burrito stand uses 3 bags of tortillas in 1 day.

So, Tobys burrito stand uses \frac{2}{3} bags of tortillas in \frac{2}{3}\times \frac{1}{3}\times 1=\frac{2}{9} days.

Thus, the number of days will 2/3 of a bag of tortillas last​ is, \frac{2}{9} days.

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Answer:

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Step-by-step explanation:

A constant correlation is essentially when the points on a scatter plot do not show any type of pattern or correlation; the points are literally scattered rather randomly, which would cause the graph to neither increase nor decrease.

Meanwhile, a positive correlation means that the points on the plot follow a line with a positive slope. In other words, it increases to the right.

Thus, the answer is C.

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4 0
3 years ago
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The perimeter of a​ standard-sized rectangular rug is 4040 ft. the length is 22 ft longer than the width. find the dimensions.
Nataly_w [17]
L = w+22

2(l+w) = 4040
2(w+22+w) = 4040
2w + 22 = 4040/2 = 2020
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w = 999ft

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2 years ago
You own a portfolio that is invested 43 percent in stock a, 16 percent in stock b, and the remainder in stock
docker41 [41]

Multiply the investment fraction by the corresponding return, and add the products. The given fractions add to 59%, so the remainder is 41%. (The total of the fractions is 100%—all of the portfolio.)

... 0.43*9.1% + 0.16*16.7% + 0.41*11.4%

... = 3.913% + 2.672% + 4.674% = 11.259%

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The graph of g(x)=(0.5)x+4 is shown. Which equation is an asymptote of this function? y = 0 y = 4 x = 4 x = 0
Alexandra [31]

we are given

g(x)=(0.5)^x+4

we can see that

there is no value of x for which g(x) is not defined

so, no vertical asymptote exists

now, we will find horizontal asymptote

\lim_{x \to \infty} g(x)= \lim_{x \to \infty}((0.5)^x+4 )

\lim_{x \to \infty} g(x)= (\lim_{x \to \infty} (0.5)^x+\lim_{x \to \infty} 4 )

\lim_{x \to \infty} g(x)= 0+4

so, we get

horizontal asymptote as

y= 4............Answer

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