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d1i1m1o1n [39]
3 years ago
8

According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 15x11 – 6x8 + x3 – 4x + 3?

Mathematics
2 answers:
docker41 [41]3 years ago
8 0

<u>Answer-</u>

<em>All the potential rational roots are,</em>

\pm \frac{1}{15}, \pm \frac{1}{5},\pm \frac{1}{3},\pm \frac{3}{5},\pm 1, \pm 3,

<u>Solution-</u>

<u>Rational Root Theorem</u>

f(x)=a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+.......+a_1x+a_0\ \ \ and\ a_n\neq 0

All the potential rational roots are,

\pm (\dfrac{\text{factors of}\ a_0}{\text{factors of}\ a_n})

The given polynomial is,

f(x) = 15x^{11}-6x^8+x^3-4x+3

Here,

a_n=15,\ a_0=3

\text{factors of}\ 15=1,3,5,15\\\\\text{factors of}\ 3=1,3

The potential rational roots are,

=\pm \frac{1}{1},\pm \frac{1}{3}, \pm \frac{1}{5}, \pm \frac{1}{15}, \pm \frac{3}{1}, \pm \frac{3}{3}, \pm \frac{3}{5}, \pm \frac{3}{15}

=\pm 1,\pm \frac{1}{3}, \pm \frac{1}{5}, \pm \frac{1}{15}, \pm 3, \pm 1, \pm \frac{3}{5}, \pm \frac{1}{5}

= \pm \frac{1}{15}, \pm \frac{1}{5},\pm \frac{1}{3},\pm \frac{3}{5},\pm 1, \pm 3,

AlexFokin [52]3 years ago
6 0

Answer:

A

Step-by-step explanation:

Hope this helps

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