Answer:
Step-by-step explanation:
If Δ JKL ~ Δ JHG , then
=
≠
⇒ triangles are not similar
Answer:
-8, -6, -4, -3, 0, 9, 12, 15
Step-by-step explanation:
X=2
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Answer:
(x, y) = (-0.6, 0.8) or (1, 4)
Step-by-step explanation:
Use the second equation to substitute for y in the first.
(x -1)² +((2x +2) -2)² = 4
x -2x +1 + 4x² = 4 . . . . . . . eliminate parentheses
5x² -2x -3 = 0 . . . . . . . . . . subtract 4, collect terms
Now we can rearrange the middle term to ease factoring by grouping.
(5x² -5x) +(3x -3) = 0
5x(x -1) +3(x -1) = 0
(5x +3)(x -1) = 0
The values of x that make these factors zero are ...
x = -3/5, x = 1
The corresponding values of y are ...
y = 2(-3/5)+2 = 4/5 . . . . for x = -3/5
y = 2(1) +2 = 4 . . . . . . . . for x = 1
The solutions are: (x, y) = (-3/5, 4/5) or (1, 4).
___
A graphing calculator verifies these solutions.
The formula is
a^3 - b^2 = (a - b)(a^2 + ab + b^2) so plugging in the given values:-
a = cube root of 125 = 5 and b = cube root of 27 = 3 , we get:-
125 - 27 = (5 - 3)(5^2 + 5*3 + 3^2)
= 2 * 49
= 98 answer