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iogann1982 [59]
3 years ago
7

%7D%5E%7B2%7D%20%20-%208%20%7By%7D%5E%7B2%7D%29%20%20" id="TexFormula1" title="( \frac{1}{7} x - \frac{1}{8}y) \times (7 {x}^{2} - 8 {y}^{2}) " alt="( \frac{1}{7} x - \frac{1}{8}y) \times (7 {x}^{2} - 8 {y}^{2}) " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
egoroff_w [7]3 years ago
7 0

Answer:

x^{3}-\frac{8}{7} xy^{2} -\frac{7}{8}x^{2}y+y^{3}

Step-by-step explanation:

(\frac{1}{7} x -\frac{1}{8} y)*(7x^{2} - 8y^{2}) =\frac{1}{7} x*7x^{2} -\frac{1}{7} x*8y^{2}-\frac{1}{8} y*7x^{2} + \frac{1}{8} y*8y^{2}=\\\\=x^{3}-\frac{8}{7} xy^{2} -\frac{7}{8}x^{2}y+y^{3}

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