Which is bigger 4 pints or 4 quarts

2x2 − 2z4 + y2 − x2 + z4 if x = −4, y = 3, and z = 2.

Setler [38]

answer: 9

Step-by-step explanation:

x = - 4; y = 3; z = 2;2 x² - 2 z^4 + y² - x² + z^4 = = 2 * (-4)² - 2 * 2^4 + 3² - ( -4)² + 2^4 == 2 * 16 - 2 * 16 + 9 - 16 + 16 = = 32 - 32 + 9 - 16 + 16 = 9

5 0

3 years ago

Draw a vertical line through a normal distribution for

m_a_m_a [10]

The proportion in the tail with regards to the z scores will be:

z = 1.00 = 0.1587
z = 0.50 = 0.3085
z = -1.25 = 0.1056
z = -0.40 = 0.3446

<h3>How to calculate the values?</h3>

a. z= 1.00

P(z > 1.00) = 1 - P(Z < 1.00)

= 1 - 0.8413

= 0.1587

The tail will be on the right side.

The proportion of the tail will be 0.1587.

b. z = 0.50

P(z > 0.50) = 1 - P(Z < 0.50)

= 1 - 0.6915

= 0.3085

The tail will be on the right side.

The proportion of the tail will be 0.3085

c. z= -1.25

P(z < -1.25)

= 0.1056

The tail will be on the left side.

The proportion of the tail will be 0.1056.

d. z= -0.40

P(z < -0.40)

= 0.3446

The tail will be on the left side.

The proportion of the tail will be 0.3446.

Learn more about z scores on:

brainly.com/question/25638875

#SPJ1

8 0

2 years ago

Today, Olivia has $127 in her savings account. She will deposit $5 into the account each week. Given x>0 , which function rep

nevsk [136]

C because it's x means weeks so $5 a week is 5x and she already has 127 so 5x+127.

7 0

3 years ago

6.24%200 show your work?

Jlenok [28]

$187.52 is 6.24% off of 200 and the amount saved is $12.48. If this is not what you meant let me know. The math is $200 × (1 - 6.24) = $187.52. Hope this helps!

7 0

3 years ago

Read 2 more answers

Estimate the integral ∫6,0 x^2dx by the midpoint estimate, n = 6

Anettt [7]

Splitting up the interval [0, 6] into 6 subintervals means we have

$[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]$

and the respective midpoints are $\dfrac12,\dfrac32,\dfrac52,\ldots,\dfrac{11}2$ . We can write these sequentially as ${x_i}^*=\dfrac{2i+1}2$ where $0\le i\le5$ .

So the integral is approximately

$\displaystyle\int_0^6x^2\,\mathrm dx\approx\sum_{i=0}^5({x_i}^*)^2\Delta x_i=\frac{6-0}6\sum_{i=0}^5({x_i}^*)^2=\sum_{i=0}^5\left(\frac{2i+1}2\right)^2$

Recall that

$\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6$
$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$
$\displaystyle\sum_{i=1}^n1=n$

so our sum becomes

$\displaystyle\sum_{i=0}^5\left(\frac{2i+1}2\right)^2=\sum_{i=0}^5\left(i^2+i+\frac14\right)$
$=\displaystyle\frac{5(6)(11)}6+\frac{5(6)}2+\frac54=\frac{143}2$

8 0

3 years ago