Answer:
3x²+(-27x) +0
Step-by-step explanation:
The given expression is :
x + 3x² – 28x
We need to solve this in the form of ax²+bx+c.
we can write the given expression as :
3x²-28x+x = 3x²-27x
= 3x²+(-27x) +0
If we compare the given expression with the general expression, we find that,
a = 3, b = -27 and c = 0
Hence, the required equation is 3x²+(-27x) +0.
Hi,
The two numbers should be 12 and 30. 12=2x2x3 while 30=2x3x5.
Their HCF is 2x3=6 and their LCM is 2x3x2x5. Because of their HFC, we know that they are both multiple of 6. Also, the question says they both are GREATER than 6, so they can’t be 6 but are 6 times “something”. Thanks to the LCM, we know that “something” is equal to 2 for the first number and to 5 for the second one, the numbers hence being 12 and 30.
I hope this helps. If I was not clear enough or if you’d like further explanation please let me know. Also, English is not my first language, so I’m sorry for any mistakes.
Answer:
0.6604 m
Step-by-step explanation:
The convertion from inches to meters is 1 inch= 0.024 meters, so:
26 inches = 26 inch* 0.024 meters/inch = 0.6604 meters
Good luck!
Answer: 2/6 and 1/3
Step-by-step explanation: Equivalent fractions are fractions that have the same value but have different top and bottom numbers.
We can find 1 equivalent fraction by dividing the numerator and the denominator by 2 and we get 2/6. We can also reduce 2/6 by dividing the numerator and the denominator by 2 and we get 1/3.
So two equivalent fractions for 4/12 would be 2/6 and 1/3.
Which point could be removed in order to make the relation a function? (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}
stepan [7]
We are given order pairs (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}.
We need to remove in order to make the relation a function.
<em>Note: A relation is a function only if there is no any duplicate value of x coordinate for different values of y's of the given relation.</em>
In the given order pairs, we can see that (0, –2) and (0, 8) order pairs has same x-coordinate 0.
<h3>So, we need to remove any one (0, –2) or (0, 8) to make the relation a function.</h3>
