Answer:
$950 in order to maximize the revenue.
Explanation:
The computation of monthly rent in order to maximize revenue is shown below:-
R (x) = Rent price per unit × Number of units rented
= ($900 + $10 x) × (100 - x)
= $90,000 - 900 x + 1000 x - 10 x^2
R (x) = -10 x^2 + 100 x + $90,000
Here to maximize R (x), we will find derivative and equal it to zero
R1 (x) = -20 x + 100 = 0
20 x = 100
x = 5
Therefore the monthly rent is p(5) = $900 + 10(5)
= $900 + 50
= $950 in order to maximize the revenue.