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ElenaW [278]
3 years ago
15

Given sin(theta)=3/5, find a, the other angle in the right triangle.

Mathematics
2 answers:
Slav-nsk [51]3 years ago
7 0

In the given triangle, one angle is a right angle.

Given \sin \Theta =\frac{3}{5}

\Theta =\arcsin \frac{3}{5}

\Theta = 36.8^{\circ}=37^{\circ}

So, the other angle is 37 degrees.

Now, we have to find the third angle.

By using angle sum property in a triangle.

90^{\circ}+37^{\circ}++ third angle = 180^{\circ}

Third angle = 180^{\circ}-127^{\circ}

= 53^{\circ}

So, the other angles are 37 degrees and 53 degrees.

Sliva [168]3 years ago
5 0

\sin( \alpha )  =  \frac{3}{5}  \\   \alpha  = 37 \\  \beta  = 53
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