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Trava [24]
3 years ago
12

Which linear equality will not have a shared solution set with the graphed linear inequality? y > Two-fifthsx + 2 y Negative

two-fifthsx – 5 y < Five-halvesx + 2
Mathematics
1 answer:
miss Akunina [59]3 years ago
6 0

Answer:

The answer is B

Step-by-step explanation:

Im on Edg right now and I got the answer

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Identify the situation that involves opposite quantities adding up to zero Climbing up 6 feet and climbing down 4 feet Hiking 10
ivolga24 [154]

9514 1404 393

Answer:

  (b)  Hiking 10 feet due north, then hiking 10 feet due south

Step-by-step explanation:

Any pair of numbers that totals zero will be a pair of opposites. The offered choices are ...

  +6 -4 = 2 . . . not zero

  +10 -10 = 0

  +2 -3 = -1 . . . not zero

  +5 -3 = 2 . . . not zero

Hiking 10 feet due north, then hiking 10 feet due south is a situation involving opposite numbers adding up to zero.

3 0
3 years ago
Can someone pls help
Katyanochek1 [597]

Answer:

x = 35

Step-by-step explanation:

Sum of angles of triangle = 180°

  • 60 + 60 + 4x - 80 = 180
  • 40 + 4x = 180
  • 4x = 140
  • x = 140/4
  • x = 35°
3 0
2 years ago
Read 2 more answers
Use the given data to find the minimum sample size required to estimate a population proportion or percentage. margin of​ error:
guapka [62]
Minimum required sample size for a desired margin of error and confidence level when it is a proportion problem: n = (z2÷margin of error2)*p-hat*q-hat

The maximum value of p-hat*q-hat occurs where p-hat = .5 (found by taking the derivative of (p-hat)*(1-p-hat) and setting it equal to 0 to find the maximum. n = ( 2.5762( for 99% confidence interval)÷.0482 )*.5*.5 = 720.028 or 721 
7 0
3 years ago
Thereeeeeeeeeeeeeeeeeeeeeeee
lesantik [10]

Answer:

1. 0.5%

2. 3%

3. 20%

4. 250%

5. 500%

hope this helps have a blessed day :)

4 0
3 years ago
if you are dealt 4 cards from a shuffled deck of 52 cards, find the probability of getting one Queen and three king​
Elza [17]

Answer: \frac{16}{270725}

This is the same as writing 16/270725

========================================================

Explanation:

There are 4 ways to draw a queen and 4 ways to select three kings (think of it like saying there are 4 ways to leave a king out). That produces 4*4 = 16 ways total to draw the four cards we want.

This is out of _{52}C_4 = 270,725 ways to select four cards without worrying if we got a queen and/or king. The steps to finding this number are shown below.

Divide the two values found to get the final answer \frac{16}{270725}

--------------------

Scratch Work:

Computing the value of _{52}C_4

Plug in n = 52 and r = 4 into the combination formula below

_{n} C _{r} = \frac{n!}{r!*(n-r)!}\\\\_{52} C _{4} = \frac{52!}{4!*(52-4)!}\\\\_{52} C _{4} = \frac{52*51*50*49*48!}{4!*48!}\\\\_{52} C _{4} = \frac{52*51*50*49}{4!} \ \ \text{ .... the 48! terms cancel}\\\\_{52} C _{4} = \frac{52*51*50*49}{4*3*2*1}\\\\_{52} C _{4} = \frac{6,497,400}{24}\\\\_{52} C _{4} = 270,725\\\\

We use the nCr combination formula (instead of the nPr permutation formula) because order doesn't matter with card hands.

6 0
3 years ago
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