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egoroff_w [7]
3 years ago
13

Suppose 9 glucose molecules enter glycolysis. Calculate the number of inorganic phosphate molecules required as well as the numb

er of pyruvate molecules produced.
Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
6 0

Answer:

18 inorganic phosphates and 18 pyruvates.

Explanation:

Glycolysis is the pathway involved in the metabolism of sugar. It is enzyme catalyze and converts glucose into pyruvate and a Hydrogen ion.

The free energy released are the used to form high-energy molecules such as ATP and NADH.

The net ATP production of Glycolysis involving a molecule of Glucose are 2 ATPs ,2 NADH and 2 pyruvates.

If 9 molecules of glucose enter glycolysis,then it has to be multiplied by 9 to give 18 pyruvates and 18 net ATPs

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How to separate crystals from solution​
tatiyna

Answer:

If a saturated hot solution is allowed to cool, the solute is no longer soluble in the solvent and forms crystals of pure compound. Impurities are excluded from the growing crystals and the pure solid crystals can be separated from the dissolved impurities by filtration.

6 0
1 year ago
if 28.5 g of calcium hydroxide is dissolved in enough water to make 185g of solution what is the percent by mass of calcium hydr
DENIUS [597]

The percent by mass of calcium hydroxide in the solution : 15.41%

<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

Mass of solute (Ca(OH₂-Calcium hydroxide) : 28.5

Mass of solution = 185 g

\tt \%mass=\dfrac{mass~solute}{mass~solution}\times 100\%\\\\\%mass=\dfrac{28.5~g}{185~g}\times 100\%\\\\\%mass=15.41\%

6 0
3 years ago
How many moles of K2SO4 are in 15.0 grams of K2SO4
uysha [10]
Molar mass K₂SO₄ = 174.259 g/mol

n =  \frac{m}{M}

n =  \frac{15.0 g}{174.259g/mol}

n = 0.0860 moles

hope this helps!
5 0
2 years ago
Read 2 more answers
Before a new medicine is approved, scientists study the effects the medicine has on different parts of the body. Often, a medici
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different cell specialized in different function

6 0
3 years ago
An enzyme can catalyze a reaction with either of two substrates, S1 or S2. The Km for S1 was found to be 2.0 mM, and the Km, for
Lera25 [3.4K]

Answer:

100.5 ≈ 101

Explanation:

Km for S1 = 2.0 mM

Km for S2 = 20 mM

Given that : S1 = S2 =  hence Vmax for either S1 or S2 can represent

The Vmax can be calculated using the data Given and equation below

Vo = Vmax [s] / ( Km + [s] )  ------ (1)

Vo = 0.5

[s] = 0.1 mM

km = 20 mM

making Vmax subject of  equation 1

Vmax = 0.5 ( 20.1 mM) / (0.1 mM )

         = 100.5 ≈ 101

3 0
3 years ago
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