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Sphinxa [80]
3 years ago
13

An electromagnetic wave has a wavelength of 0.12 meters. what is that in nanometers?

Chemistry
1 answer:
tino4ka555 [31]3 years ago
7 0

Answer:

1.2 × 10⁸ m

Explanation:

You want to convert metres to nanometres.

Recall that the multiplying prefix nano- means × 10⁻⁹, so

1 nm = 1 × 10⁻⁹ m

The conversion factor is either \frac{\text{1 nm} }{10^{-9} \text{m}} or \frac{10^{-9} \text{m} }{\text{1 nm}}.

You choose the one that has the desired units (nm) on top. Then

\lambda = \text{0.12 m} \times \frac{\text{1 nm} }{10^{-9} \text{m}} = 1.2 \times 10^{8} \text{ nm}

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Answer:

option A = S(s) + O₂(g)   →   SO₂ (s)

Explanation:

Chemical equation:

S(s) + O₂(g)   →   SO₂ (s)

when sulfur burned in the presence of oxygen it produce sulfur dioxide. The sulfur dioxide can further react with oxygen to produce sulfur trioxide and then react with water to form sulfuric acid.

Uses of sulfur dioxde:

It is used as a solvent and reagent in laboratory.

Sulfur dioxide is used to produce sulfuric acid.

It is used as a disinfectant

It is also used as a reducing agent.

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The pressure in a car tire is 198 kPa at 27°C. After a long drive, the pressure
AlekseyPX

Answer : The temperature of the air in the tire is, 341 K

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T

or,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

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P_2 = final pressure = 225 kPa

T_1 = initial temperature = 27^oC=273+27=300K

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Now put all the given values in the above equation, we get:

\frac{198kPa}{300K}=\frac{225kPa}{T_2}

T_2=340.9K\approx 341K

Therefore, the temperature of the air in the tire is, 341 K

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