Answer: 8 dots would be needed to represent the outer electrons for an atom of neon in an electron dot diagram.
Explanation:
Electron-dot diagram is also known as Lewis-dot structure. It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule. The valence electrons are represented by 'dot'.
As atomic number of neon is 10 and we know that neon has 10 electrons with electronic configuration of 2,8 and thus has '8' valence electrons.
Therefore, the total number of valence electrons is 8 and 8 dots would be needed to represent the outer electrons for an atom of neon in an electron dot diagram.
Explanation:
It'd be better to use cyclohexane. The possible explanation is that the freezing temperature will change by 20.1 degrees for each mole of substance added to 1 kg of cyclohexane, although the same amount added to naphthalene will change its freezing point just by 6.94 degrees.
It is so much easier to identify a larger change more adequately than a smaller one. You would actually not have a 1 molal solution in operation, so the variations in freezing points would be even smaller than the ones already described.
Explanation:
SADMEP
-2(bx-5) = 16 distribute
-2bx +10 = 16 subtracte
-10 -10
-2bx = 6
divide by -2x (on both sides)
b = -3x
from ICE table
H2(g) + I2 (g )↔ 2HI(g)
equ 0.958 0.877 0.02 first mix1
0.621 0.621 0.101 sec mix2
Kp1 = P(HI)^2 / p(H2)*p(I2) for mix 1
= 0.02^2 / 0.958*0.877
= 4.8x10^-4
Kp2 = P(HI)^2 / P(H2)* P(I2) for mix 2
= 0.101^2/ 0.621*0.621
= 0.0265
we can see that Kp1< Kp2 that means that the sec mixture is not at equilibrium. It will go left to reduce its products and increase reactant to reduce the Kp value to achieve equilibrium.
and the partial pressure of Hi when mix 2 reach equilibrium is:
4.8x10^-4 = P(Hi)^2 / (0.621*0.621)
∴ P(Hi) at equilibrium = 0.0136 atm
