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2 years ago

11

a rectangle that is 2 inches by 3 Inches has been scaled by factor of 7 suppose you want to scale the copy back to its original

size what scale factor would you use?

1 answer:

DedPeter [7]2 years ago

5 0

It would be 1/7 since you essentially are dividing by 7 to cancel out the original scaling.

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A movie theater sends out a coupon for % off the price of a ticket. Write an equation for the situation, where y is the price

natali 33 [55]

The orginal price is 65

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2 years ago

The quality-control manager at a compact fluorescent light bulb (CFL) factory needs to determine whether the mean life of a la

stira [4]

<h2>Answer with explanation:-</h2>

Let $\mu$ be the population mean .

By observing the given information, we have :-

$H_0:\mu=7450\\\\H_a:\mu\neq7450$

Since the alternative hypotheses is two tailed so the test is a two-tailed test.

We assume that the life of a large shipment of CFLs is normally distributed.

(a) Given : Sample size : n=81 , since n>30 so we use z-test.

Sample mean : $\overline{x}=7240$

Standard deviation : $\sigma=1350$

Test statistic for population mean :-

$z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

$\Rightarrow\ z=\dfrac{7240-7450}{\dfrac{1350}{\sqrt{81}}}\\\\\Rightarrow\ z=-1.4$

The critical value (two-tailed) corresponds to the given significance level :-

$z_{\alpha/2}=z_{0.025}=1.96$

Since the observed value of z (-1.4) is less than the critical value (1.96) , so we do not reject the null hypothesis.

Hence, we conclude that we have enough evidence to accept that the mean life is different from 7450 hours .

(b) The p-value : $2P(z>-1.4)=0.1615$ , it means that the probability that the life of CFLs less than 7240 and greater than 7240 is 0.1615.

(c) The confidence interval for population mean is given by :-

$\overline{x} \pm\ z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}\\\\=7240\pm(1.96)\dfrac{1350}{\sqrt{81}}\\\\=7240\pm294\\\\=(6946,7534)$

,

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2 years ago

Find the range of f(x)=-3x+1 if the domain is (-3,0,5)

wariber [46]

<em>HOPE</em><em> </em><em>THIS</em><em> </em><em>WILL</em><em> </em><em>HELP</em><em> </em><em>U</em><em>.</em><em>.</em><em> </em><em>:</em><em>)</em>

6 0

2 years ago

A stadium has 50,000 seats. Seats sell for $28 in Section A, $24 in Section B, and $20 in Section C. The number of seats in Sect

Pepsi [2]

Answer:

Section A holds 25,000 seats, section B holds 14,500 seats and section C holds 10,500 seats.

Step-by-step explanation:

From the information given you can write the following equations:

A+B+C=50,000 (1)

28A+24B+20C=1,258,000 (2)

A=B+C (3)

A= number of seats in section A

B= number of seats in section B

C= number of seats in section C

You can replace (3) in (1) and (2) to get two equations:

B+C+B+C=50,000

2B+2C=50000

28(B+C)+24B+20C=1,258,000

28B+24B+28C+20C=1,258,000

52B+48C=1,258,000

The two equations are:

2B+2C=50000 (4)

52B+48C=1,258,000 (5)

You can isolate B in (4):

2B=50,000-2C

B=(50,000/2)-(2C/2)

B=25,000-C

Now, you can replace B in (5):

52(25,000-C)+48C=1,258,000

1,300,000-52C+48C=1,258,000

1,300,000-1,258,000=4C

42,000=4C

C=42,000/4

C=10,500

Now, you can replace the value of C in B=25,000-C:

B=25,000-10,500

B=14,500

Finally, you can replace the values of B and C in A=B+C to find A:

A=14,500+10,500

A=25,000

According to this, the answer is that section A holds 25,000 seats, section B holds 14,500 and section C holds 10,500.

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3 years ago

kupik [55]

-5+1+-2+9v+-5v

-3+1+4v

-2+4v

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2 years ago