Which set of numbers cannot represent the lengths of the sides of a triangle?

3|x| = 18 show work please

Alinara [238K]

I think the answer is 6 since u multiply them

8 0

3 years ago

-1.398 = 2.2 + n/-5.53<br> Does this look good so far? <br> -1398 = 2200 + n/5530 - 2200

insens350 [35]

Answer:

n = 19.89694

Step-by-step explanation:

You can work the problem using decimal numbers. There is no need to convert everything to integers. Trying to do so just gets you in trouble.

Subtract 2.2 from both sides:

-1.398 -2.200 = n/-5.53

-3.598 = n/-5.53

Now, multiply both sides by -5.53:

(-5.53)(-3.598) = n = 19.89694

_____

The one rule that cannot be violated in algebra is that <em>you must do the same thing to both sides of the equation</em>.

_____

Your "solution" so far has a couple of errors. The first is that you have apparently multiplied all of the numbers by 1000. Unfortunately, when you multiply a denominator by 1000, it is the same as dividing by 1000. So, you have multiplied the left side by 1000, multiplied one term on the right by 1000 and divided another term on the right by 1000. This turns the equation into something different than what you started with, and will give a wrong answer.

The second error is that you have subtracted 2200 only from the right side. This, too, will turn the equation into something different than what you started with, and will give a wrong answer.

7 0

3 years ago

A teacher has 3 hours to grade all the papers submitted by the 35 students in her class. She gets through the first 5 papers in

Andreyy89

So, she has 3hrs to grade all papers, for 35 students.. alrite.

the first 5, she does them in 30minutes.. what's the speed rate? well, 5/30 or 1/6

now, she has still 2 hours and a half, or 150 minutes, to do the remaining 30 papers... she has to work at a rate of 30/150 then... which is 1/5 simplified.

now if we take 1/6 as the 100%, what is 1/5 in percentage then?

$\bf \begin{array}{ccllll}
rate&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\frac{1}{6}&100\\\\
\frac{1}{5}&x
\end{array}\implies \cfrac{\frac{1}{6}}{\frac{1}{5}}=\cfrac{100}{x}\implies \cfrac{1}{6}\cdot \cfrac{5}{1}=\cfrac{100}{x}\implies \cfrac{5}{6}=\cfrac{100}{x}
\\\\\\
x=\cfrac{6\cdot 100}{5}\implies x=120$

so 1/5 is 120% in relation to 1/6... meaning the rate of 1/5 she needs to move through, namely 1 paper every 5 minutes, is 20% faster than 1/6.

8 0

3 years ago

Read 2 more answers

A) Write each expression in expanded form. B) Then calculate the value of the

Tatiana [17]

A) (3)² = 3 × 3 and 10(8)² = 10 × 8 × 8

B) (3)² = 9 and 10(8)² = 640

For any number x, the square of the number denoted by (x)² is equal to 2 times x multiplied by itself or x*x.

Here, we are given two expressions- (3)² and 10(8)²

we need to write both of them in expanded form and then write their values.

Expanded form of (3)² is 3 × 3

The value of the expression (3)² will be-

(3)² = 3 × 3 = 9

Similarly, expanded form of 10(8)² is 10 × 8 × 8

The value of the expression 10(8)² will be-

10(8)² = 10 × 8 × 8 = 640

Learn more about expanded form here-

https://brainly.in/question/19612773

#SPJ9

8 0

2 years ago

A website manager has noticed that during the evening hours, about 5 people per minute check out from their shopping cart and m

Over [174]

Answer:

a) Poisson distribution

b) 99.33% probability that in any one minute at least one purchase is made

c) 0.05% probability that seven people make a purchase in the next four minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

5 people per minute check out from their shopping cart and make an online purchase.

This means that $\mu = 5$

a) What model might you suggest to model the number of purchases per minute? 

The only information that we have is the mean number of an event(purchases) in a time interval. Each event is also independent fro each other. So you should suggest the Poisson distribution to model the number of purchases per minute.

b) What is the probability that in any one minute at least one purchase is made? 

Either no purchases are made, or at least one is. The sum of the probabilities of these events is 1. So

$P(X = 0) + P(X \geq 1) = 1$