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3 years ago

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janelle has $75. She buys jeans that are discounted 30% and then uses an in-store coupon for $10 off the discounted price. After

paying $3.26 in sales tax, she receives $17.34

1 answer:

kicyunya [14]3 years ago

7 0

If you want to the know the total price of the jeans, with discount coupon and sales tax then it's $15.76

$75 x 0.30 = $22.50

$22.50 - $10 = $12.50

$12.50 + $3.26 = $15.76

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dolphi86 [110]

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3 years ago

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KATRIN_1 [288]

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mina [271]

a) Since both limits are <em>distinct</em> and do not exist, we conclude that x = - 1 is not part of the domain of the <em>rational</em> function.

b) The function $f(x) = \frac{x}{x^{2}+ x}$ is equivalent to the function $g(x) = \frac{1}{x + 1}$ .

<h3>How to determine whether a limit exists or not</h3>

According to theory of limits, a function f(x) exists for x = a if and only if $\lim_{x\to a^{-}} f(x) = \lim_{x \to a^{+}} f(x)$ . This criterion is commonly used to prove continuity of functions.

<em>Rational</em> functions are not continuous for all value of x, as there are x-values that make denominator equal to 0. Based on the figure given below, we have the following <em>lateral</em> limits:

$\lim_{x \to -1^{-}} \frac{x}{x^{2}+x} = - \infty$

$\lim_{x \to -1^{+}} \frac{x}{x^{2}+x} = + \infty$

Since both limits are <em>distinct</em> and do not exist, we conclude that x = - 1 is not part of the domain of the <em>rational</em> function.

In addition, we can simplify the function by <em>algebra</em> properties:

$\frac{x}{x^{2}+ x} = \frac{x}{x\cdot (x + 1)} = \frac{1}{x + 1}$

$g(x) = \frac{1}{x + 1}$

The function $f(x) = \frac{x}{x^{2}+ x}$ is equivalent to the function $g(x) = \frac{1}{x + 1}$ .

To learn more on lateral limits: brainly.com/question/21783151

#SPJ1

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2 years ago

If n√a=r , then which of the following are true statements? Check all that apply. A. r^n=a B. a^1/n=r C. a^r=n D. n^1/r=a

sergij07 [2.7K]

I'm interpreting this has 'the nth root of a = r'.

n the root of a = a ^(1/n)

so its B

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3 years ago