Set y1=x+30 and y2=x^2, plugged those into the distance formula assuming x=a<span>,
</span><span>
d=rad(<span>(y2−y1<span>)^2)
</span></span></span><span>d(x)=x^2−x−30
</span>All you have to do is to maximize the given quadratic function. I hope that this is the answer that you were looking for and it has helped you.
3/c + 7 = 8/c + 6
3/c = 8/c - 1
-5/c = -1
c = 1/5
Answer:
I'd say about 50/50 cuz say there is 6 red cards and 7 black cards then it depends on the luck of the draw
Step-by-step explanation:
ik my answer sucks but thats what i think
Answer:

Equation:
![\bold{8+\left\{22\cdot\left[15+\left(14\cdot \:2\right)\right]\right\}}](https://tex.z-dn.net/?f=%5Cbold%7B8%2B%5Cleft%5C%7B22%5Ccdot%5Cleft%5B15%2B%5Cleft%2814%5Ccdot%20%5C%3A2%5Cright%29%5Cright%5D%5Cright%5C%7D%7D)
Step ByStep Explanation:
Follow PEMDAS Order of Operations
[ Solve
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[ Rewrite Equation ]

[ Solve
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