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ladessa [460]
3 years ago
11

Solve by using the perfect squares method.

Mathematics
2 answers:
Verizon [17]3 years ago
4 0
X²+16x+64=(x+8)² (because (a+b)²=a²+2ab+b² => perfect square)
So you have to find x which will make (x+8)²=0
which is true when x+8=0
x=-8 
That's a.
Hope it helps!
Julli [10]3 years ago
3 0
X² + 16x + 64 = 0
x² + 2 * x * 8 + 8² = 0

Now, sing the formula (a + b)² = a² + 2ab + b² , we get,

(x + 8)² = 0

Square rooting on both sides, we get,

x + 8 = √0

x + 8 = 0

x = - 8    <== that's your answer!!!

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The given sequence is
a₁, a₂, ..., a_{n}

Because the given sequence is an arithmetic progression (AP), the equation satisfied is
a_{n}=a_{1}+(n-1)d
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d =  the common difference.

The common difference may be determined as
d = a₂ - a₁

The common difference is the difference between successive terms, therefore
d = a₃ - a₂ = a₄ - a₃, and so on..

The sum of the first n terms is
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Example:
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8 0
3 years ago
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