Solve by using the perfect squares method.
2 answers:
X²+16x+64=(x+8)² (because (a+b)²=a²+2ab+b² => perfect square) So you have to find x which will make (x+8)²=0 which is true when x+8=0 x=-8 That's a. Hope it helps!
X² + 16x + 64 = 0 x² + 2 * x * 8 + 8² = 0 Now, sing the formula (a + b)² = a² + 2ab + b² , we get, (x + 8)² = 0 Square rooting on both sides, we get, x + 8 = √0 x + 8 = 0x = - 8 <== that's your answer!!!
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