Which number is the c losest approximation of v39? o 6.2 o 6.5 o 7.5 o 7.7

Sue has $100 saved to buy concert tickets that go on sale in 8 weeks. She plans to save $15 every 2 weeks. Will Sue have enough

Katen [24]

Answer:

she wont have enough money.

Step-by-step explanation:

she is saving money every 2 weeks. 8 divided by 2 is 4, so we'd have 15 x 4 which is 60. then we'd add it to 100, which would be 160, then divide it by 4, which would roughly come down to 40 dollars each, meaning we would not have enough money for 4 tickets

5 0

2 years ago

Read 2 more answers

The circumference of a circle is 113.04 centimetres. What is the circle's radius?

Drupady [299]

Answer:

18 centimeters

Step-by-step explanation:

Divide the circumference by π, or 3.14 for an estimation. The result is the circle's diameter.

Divide the diameter by 2.

There you go, you found the circle's radius

6 0

2 years ago

C=5p+215 for p the formula c=5p + 215 relates c, the total cost in dollars of hosting a birthday party at a skating rink,to p, t

Nezavi [6.7K]

it should be 17, people

5 0

3 years ago

Jason is pulling a box across the room. He is pulling with a force of 19 newtons and his arm is making a 30 angle with the horiz

Cerrena [4.2K]

We are to solve for the vertical and horizontal component of the force he is pulling with.

1. The vertical component of Jason's force is 9.5Newtons.

2.The horizontal component of Jason's force is 2.67Newtons.

3. Therefore, the net force in the vertical direction is -12.5Newtons.

4.Therefore, Resultant, R is 72.11

Question 1:

If Jason is pulling with a force of 19 Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 19 × Sin 30° = 9.5 Newtons.

The vertical component of Jason's force is 9.5 Newtons.

Question 2:

Also,If Jason is pulling with a force of 14 Newtons and his arm is at an angle of 79° with the horizontal.

By resolving Jason's force of pull in the horizontal direction, Fx = 14 × Cos79° = 2.67 Newtons.

The horizontal component of Jason's force is 2.67Newtons.

Question 3:

If Jason is pulling with a force of 23Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 23 × Sin 30° = 11.5Newtons.

The vertical component of Jason's force of pull is, 11.5Newtons.

If the box weighs 24Newtons.

By treating up as the +ve vertical direction and down as the -ve vertical direction,

Therefore, the weight of the box acts in the -ve vertical direction, while Jason's vertical force component acts in the +ve vertical direction.

Therefore, the net force in the vertical direction is = 11.5Newtons + (-24Newtons)

Therefore, the net force in the vertical direction is -12.5Newtons.

Question 4:

If there are two forces at right angles to eachother, one of magnitude, 68 and the other of magnitude, 24.

The resultant force on the object can be obtained by Pythagoras theorem (Triangle law of forces).

Resultant, R = √(68²+24²) = √5200.

Therefore, Resultant, R = 72.11