All categories

3 years ago

Find (f∘g)(x) if f(x) = 2x - 1 and g(x) = x + 2.A.2x - 3B.2x + 1C.2x - 1D.2x + 3

Mathematics

1 answer:

V125BC [204]3 years ago

5 0

(f∘g)(x) = f(g(x)) = f(x +2)
= 2(x +2) -1
= 2x +3 . . . . . selection D

You might be interested in

HELP ASAP PLEASE!!!!! <br> what is the factorization of the polynomial below -x^2-2x+48

Veronika [31]

I HOPE IT WILL HELP YOU. I DID HOW I KNOW .

8 0

3 years ago

19. A quadratic equation is shown below.

victus00 [196]

Answer:

$\{\sqrt b, -\sqrt b\}$

Step-by-step explanation:

Given

$a^2 - b = 0$

Required

Determine the solution

Since b is a perfect square, the equation can be expressed as:

$a^2 - (\sqrt b)^2 = 0$

Apply difference of two squares:

$(a - \sqrt b)(a + \sqrt b) = 0$

Split:

$(a - \sqrt b)= 0 \ or\ (a + \sqrt b) = 0$

Remove brackets:

$a - \sqrt b= 0 \ or\ a + \sqrt b = 0$

Make a the subject in both equations

$a =\sqrt b \ or\ a =-\sqrt b$

The solution can be represented as:

$\{\sqrt b, -\sqrt b\}$

6 0

3 years ago

What is 15% of 60? Create a model to prove your answer (this is the question. I didn't really understand today's lesson in class

skelet666 [1.2K]

If you have instagram dm me and ill show you how to make the graph my instagram is ____ella.grace____ 4 underscores btw

8 0

3 years ago

there are 61 days in March and April mrs. Dorsey recorded 18 sunny days in March and 12 sunny days in April how many days are no

velikii [3]

61 minus 32= 29 so 29 days are not sunny.hope it helps.

7 0

3 years ago

Read 2 more answers

In a certain year, brand A of heart-rate watch cost $39.99 and brand B cost $59.99. A nonprofit community health organizatio

Oksi-84 [34.3K]

Answer:

Brand A = 21 heart-rate watches.

Brand B = 13 heart-rate watches.

Step-by-step explanation:

Let A be the number of Brand A heart watches and B be the number of Brand B heart watches.

We have been given that a nonprofit community health organization purchased 34 heart-rate watches for use at a wellness center.

We can represent this information in an equation as:

$A+B=34...(1)$

We have been given that in a certain year, brand A of heart-rate watch cost $39.99 and brand B cost $59.99 and the organization spent $1619.66 for the watches.

We can represent this information in an equation as:

$39.99*A+59.99*B=1619.66...(2)$

We will use substitution method to solve our system of equations.

From equation (1) we will get,

$A=34-B$

Substituting $A=34-B$ in equation(2) we will get,

$39.99*(34-B)+59.99*B=1619.66$

$1359.66-39.99*B+59.99*B=1619.66$

$-39.99*B+59.99*B=1619.66-1359.66$

$20*B=260$

$B=\frac{260}{20}$

$B=13$

Therefore, the organisation purchased 13 heart-rate watches of brand B.

Now let us substitute B=13 in equation (1).

$A+13=34$

$A+13-13=34-13$

$A=21$

Therefore, the organisation purchased 21 heart-rate watches of brand A.

8 0

3 years ago