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Ber [7]
3 years ago
6

DA DA DA DA DA DA DA DA DA DA DA DA DA DA DA DA DA DA DA DA DA DA DA DA DA DA DA DA DA DA

Mathematics
1 answer:
Stella [2.4K]3 years ago
5 0

Answer:

da de da da da de do re mi fa so la mi AAAAAAAAAAA

Step-by-step explanation:

I can speak the language of the gods xD

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Please help me ill mark you brainiest
Ann [662]

Answer:

55.560

Step-by-step explanation:

I imputed the equation in my calculator

5 0
3 years ago
Find the midpoint of the segment with the following end points (10,5) and (6,9)
Taya2010 [7]

Answer:

The mid-point between the endpoints (10,5) and (6,9) is:

  • \left(x,\:y\right)=\left(8,\:7\right)

Step-by-step explanation:

Let (x, y) be the mid-point

Given the points

  • (10,5)
  • (6,9)

Using the formula to find the mid-point between the endpoints (10,5) and (6,9)

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

Here:

\left(x_1,\:y_1\right)=\left(10,\:5\right),\:\left(x_2,\:y_2\right)=\left(6,\:9\right)

Thus,

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

\left(x,\:y\right)=\left(\frac{6+10}{2},\:\frac{9+5}{2}\right)

\left(x,\:y\right)=\left(8,\:7\right)

Therefore, the mid-point between the endpoints (10,5) and (6,9) is:

  • \left(x,\:y\right)=\left(8,\:7\right)
3 0
3 years ago
Rational exponent form of the square root of 10
sp2606 [1]
To make the exponent rational, for square root use 1/2.  To wit:
10^(1/2)

3 0
3 years ago
I’ve been trying sooo hard to get this and i can’t, please help
Greeley [361]

Should be 37 if you use Pythagorean theorem!

7 0
3 years ago
The number of ways in which 4 squares can be chosen at random on a chess board such that they lie on a diagonal line?.
wariber [46]

The number of ways is 364 if the number of ways in which 4 squares can be chosen at random.

<h3>What are permutation and combination?</h3>

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

It is given that:

On a chessboard, four squares are randomly selected so that they are adjacent to each other and form a diagonal:

The required number of ways:

= 2(2[C(4, 4) + C(5, 4) + C(6, 4) + C(7, 4)] + C(8, 4))

= 2[2[ 1 + 5 + 15+35] + 70]

= 364

Thus, the number of ways is 364 if the number of ways in which 4 squares can be chosen at random.

Learn more about permutation and combination here:

brainly.com/question/2295036

#SPJ4

5 0
1 year ago
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