Step-by-step explanation: In this problem, we're asked to state the domain and range for the following relation.
First of all, a relation is just a set of ordered pairs like you see in this problem. The domain is the set of all x-coordinates for those ordered pairs. So in this case the domain or D is {2, 5, -1, 0, -3}.
The range is the set of all y-coordinates for those ordered pairs. So in this case our range or R is {4, 3, -4, 9, 1}.
Answer:
see explanation
Step-by-step explanation:
the equation of a circle in standard form is
(x - a)² + (y - b)² = r²
where (a, b) are the coordinates of the centre and r is the radius
(x - 8)² + (y + 6)² = 13 is in this form
with centre = (8, - 6) and r = 
Step-by-step explanation:
f(3)=?
f(x)=2x+5
put x=3,
f(3)=2(3)+5=6+5=11
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g(2)=?
g(x)=x^2-3
put x=2,
g(2)=2^2-3=4-3=1
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g(f(-1))=?
g(x)=x^2-3
and f(-1)=2(-1)+5= -2+5=3
so g(f(-1))=3^2-3=9-3=6
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f(g(-1))=?
f(x)=2x+5
g(x)=g(-1)=(-1)^2-3=1-3= -2
f(g(-1))=2(-2)+5= -4+5=1
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g(f(x))=?
g(x)= x^2-3
put x=f(x),
g(f(x))=f(x)^2-3=(2x+5)^2-3=4x+25+20x-3=24x+25
