Answer:
C
Step-by-step explanation:
First, Karen only has $20, so her spending cannot go over this amount. That would would that she can spend exactly $20 or less than $20. We need a equal to/less than sign before $20, so answer choices A and D can easily be eliminated.
Next, the admission costs $6. This is a cost that Karen will only pay one time, so it's represented by + 6. This eliminates B, but I will still explain why C is completely correct.
Each ride costs $2, meaning that we can represent this amount with 2x, which is just $2 times the amount of rides she will go on. When fully written out, the inequality is 2x + 6 (less than or equal to sign) 20, making C the correct answer.
Answer:
Answer choices A and D. E would also be correct but it's a perfect correlation and the question said "strong but not perfect"
Step-by-step explanation:
Answer:
2 seconds
Step-by-step explanation:
You could set 3t + 16t^2 = 70 and solve for t.
OR
You could plot it on Desmos.
Answer:
Please check the explanation.
Step-by-step explanation:
<u>Calculating the area of the outer rectangle:</u>
Given
- The length outer rectangle = l = 3x - 1
- The width of outer rectangle = w = 5x + 2
Thus,
The area of the outer rectangle:





<u>Calculating the area of the inner rectangle:</u>
Given
- The length inner rectangle = l = x + 7
- The width of inner rectangle = w = x
Thus,
The area of the outer rectangle:
A = wl
= x(x+7)
= x² + 7
<u>Calculating the area of the shaded region:</u>
As
The area of the outer rectangle = 15x² + x - 2
The area of the inner rectangle = x² + 7
- The area of the shaded region can be determined by subtracting the area of the inner rectangle from the area of the outer rectangle.
Thus,
shaded region Area = Outer Rectangle Area - Inner Rectangle Area
= 15x² + x - 2 - (x² + 7)
= 15x² + x - 2 - x² - 7
= 14x² + x - 9
Therefore, the Area of the shaded region is: 14x² + x - 9
Answer:
The answer is 96
Step-by-step explanation:
The answer is 96 because 4^2 is 16 and 8 minus 2 is 6 so 16 multiplied by 6 is 96
P.S Can I have brainliest?