What do you need explained? I'd be glad to help :)
Answer:
well,the solution is x=4 y=0.... if that helps
Answer:
Solution given:
AD=1.8
AC=3.0
we have
∆ADC is a right angled triangle
Cos A=b/h
<A=cos-¹ (1.8/3)
<A=53.13°
again
∆ABC is a right angled triangle
Tan A=p/b=BC/AC
Tan 53.13×3=BC
BC=4
NOW
Area of triangle =½(AC*BC)=½(4×3)=6 <u>square </u><u>units</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>area</u><u>.</u>
Answer:
daddy chill what does the man say?
Step-by-step explanation:
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