I use my calculator
Y1 (the blue one) = x^2-2x
Graph
2nd trace minimum
X= 1 and y = -1
So the vertex is (1,-1)
Answer:
The minimum number of fish each must have caught is 90 fishes
Step-by-step explanation:
The number of fishes Tisha's net can hold = 15
The number of fishes Dana's net can hold = 18
Let the total number of fishes both Tisha and Dana caught = X
15 × A = 18 × B = X
Therefore, X is the lowest common multiple (LCM) of 15 and 18 given as follows;
15 = 3 × 5
18 = 3 × 6
Therefore, the LCM of 18 and 5 = 3 × 5 × 6 = 90
Which gives, the minimum number of fish each must have caught = 90 fishes.
The answer will be start fraction pi over 2 end fraction
Answer:
Step-by-step explanation:
KL = JK, so ΔJKL is an isocesles triangle, then m∠J = m∠L
KL is a tangent line, so ∠JKL = 90°,
so m∠J = 45°
So it's best in this case to separate both shapes so you have a rectangle and a triangle so to solve the area of a rectangle you do
The following ( picture )
So I hope this helps