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3 years ago

Suppose a triangle has two sides of length 32 and 35, and that the angle

Mathematics

1 answer:

pantera1 [17]3 years ago

3 0

Answer:

The third side is around 58.043

Step-by-step explanation:

Use the law of cosines: $c^2=a^2+b^2-2abcos(C)$

Plug in the two sides we know (into a and b) and the angle we know (into angle C).

Thus:

$c^2=32^2+35^2-2(32)(35)cos(120)$

Use a calculator:

$c^2=3369\\$

$c=58.043087...$

(Note: Make sure you're in Degrees mode.)

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OLga [1]

Answer:

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3 years ago

Tyler ate x fruit snacks, Han ate 3/4 less than that. Write an equation to represent the relationship between the number Tyler a

Citrus2011 [14]

Answer:

0.75x = y

1/4 = y

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3 years ago

The scale on a map is 2 centimeters= 50 kilometres.Two rivers on a map are located 9.3 centimeters apart.What is The actual dist

Yuki888 [10]

Answer:

The actual distance between the two rivers is 232.5 kilometers.

Step-by-step explanation:

GIven:

The scale on a map is 2 centimeters= 50 kilometres.Two rivers on a map are located 9.3 centimeters apart.

Now, to find the actual distance between the two rivers.

Let the actual distance between the two rivers is $x.$

The two rivers on the map is located apart of 9.3 centimeters.

According to the scale on the map is 2 centimeters = 50 kilometers.

So, 2 centimeters is equivalent to 50 kilometers.

Thus, 9.3 centimeters is equivalent to $x.$

Now, to solve by using cross multiplication method:

$\frac{2}{50} =\frac{9.3}{x}$

By cross multiplying we get:

$2x=465$

Dividing both sides by 2 we get:

$x=232.5\ kilometers.$

Therefore, the actual distance between the two rivers is 232.5 kilometers.

6 0

3 years ago

Write the ratio as a fraction in lowest terms. 22 to 11 1/2

fiasKO [112]

Answer:

22/1 & 23/2

Step-by-step explanation:

3 0

2 years ago

STAR Co. provides paper to smaller companies whose volumes are not large enough to warrant dealing directly with the paper mill.

mamaluj [8]

Answer:

see below

Step-by-step explanation:

In order for the problem to make sense, we have to assume typos in Patterns 2, 3, and 4. We suppose they should be (0, 0, 3, 10), (8, 0, 0, 4) and (2, 1, 2, 1).

If we let p, q, r, s, t represent the number of rolls cut to patterns 1 to 5, respectively, then we want ...

minimize 10p +10q +4r +s +t . . . . . . . total trim loss

subject to ...

0p +0q +8r +2s +7t = 5672 . . . . . . number of 12-ft rolls

6p +0q +0r +1s +1t = 1670 . . . . . . . . number of 15-ft rolls

0p +3q +0r +2s +0t = 3200 . . . . . . number of 30-ft rolls

p≥0, q≥0, r≥0, s≥0, t≥0

_____

The solution works out to be (p, q, r, s, t) = (1, 0, 253, 1600, 64) with a trim loss of 2686 feet (equivalent to 27 100-ft rolls).

Note that we have endeavored to fill the order exactly. We don't know if there are cut choices that would minimize loss further, but result in a few rolls extra of some width or another.

3 0

3 years ago