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Naily [24]
3 years ago
8

Suppose a triangle has two sides of length 32 and 35, and that the angle

Mathematics
1 answer:
pantera1 [17]3 years ago
3 0

Answer:

The third side is around 58.043

Step-by-step explanation:

Use the law of cosines:  c^2=a^2+b^2-2abcos(C)

Plug in the two sides we know (into a and b) and the angle we know (into angle C).

Thus:

c^2=32^2+35^2-2(32)(35)cos(120)

Use a calculator:

c^2=3369\\

c=58.043087...

(Note: Make sure you're in Degrees mode.)

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