3 years ago

Suppose a triangle has two sides of length 32 and 35, and that the angle

Mathematics

1 answer:

pantera1 [17]3 years ago

3 0

Answer:

The third side is around 58.043

Step-by-step explanation:

Use the law of cosines: $c^2=a^2+b^2-2abcos(C)$

Plug in the two sides we know (into a and b) and the angle we know (into angle C).

Thus:

$c^2=32^2+35^2-2(32)(35)cos(120)$

Use a calculator:

$c^2=3369\\$

$c=58.043087...$

(Note: Make sure you're in Degrees mode.)

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