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Strike441 [17]
3 years ago
8

Which of these is an example of collective voice?

Computers and Technology
2 answers:
igomit [66]3 years ago
8 0

Answer:

option C

hope it helps! please mark me brainliest..

Merry Christmas good day

Sergio039 [100]3 years ago
5 0

Answer:

c

Explanation:

You might be interested in
For this lab you will write a class to create a user-defined type called Shapes to represent different shapes, their perimeters
maw [93]
<h2>Answer:</h2>

<u />

========= Shape.java  ===========

//import the Scanner class

import java.util.Scanner;

public class Shape{

   //required fields

  private String shape;

   private double area;

   private double perimeter;

   //default constructor

  public Shape(){

       this.shape = "unknown";

       this.area = 0.0;

       this.perimeter = 0.0;

   }

   //constructor with one parameter

   public Shape(String shape){

       this.setShape(shape);

       this.area = 0.0;

       this.perimeter = 0.0;

   }

   //accessors and mutators

  public void setShape(String shape){

       this.shape = shape;

   }

  public String getShape(){

       return this.shape;

   }

   public double getPerimeter(){

       return this.perimeter;

   }

  public double getArea(){

       return this.area;

   }

  public void setPerimeter(Scanner scr){

       if(this.getShape().equals("circle")){

           System.out.println("Enter the radius of the circle");

           double radius = scr.nextDouble();

           this.perimeter = 2 * 3.142 * radius;

       }

       else if(this.getShape().equals("rectangle")){

           System.out.println("Enter the width");

           double width = scr.nextDouble();

           System.out.println("Enter the height");

           double height = scr.nextDouble();

           this.perimeter = 2 * (width + height);

       }

       else if(this.getShape().equals("square")){

           System.out.println("Enter the height or width");

           double height = scr.nextDouble();

           this.perimeter = 4 * height;

       }

       else if(this.getShape().equals("unknown")){

           System.out.println("You must define a shape first before calculating perimeter");

           this.perimeter = 0.0;

       }

       else {

           System.out.println("You must define a shape first before calculating perimeter");

           this.perimeter = 0.0;

       }

   }

   public void setArea(Scanner scr){

       if(this.getShape().equals("circle")){

           System.out.println("Enter the radius of the circle");

           double radius = scr.nextDouble();

           this.area = 3.142 * radius * radius;

       }

       else if(this.getShape().equals("rectangle")){

           System.out.println("Enter the width");

           double width = scr.nextDouble();

           System.out.println("Enter the height");

           double height = scr.nextDouble();

           this.area = width * height;

       }

       else if(this.getShape().equals("square")){

           System.out.println("Enter the height or width");

           double height = scr.nextDouble();

           this.area = height * height;

       }

       else if(this.getShape().equals("unknown")){

           System.out.println("You must define a shape first before calculating area");

           this.area = 0.0;

       }

       else {

           System.out.println("You must define a shape first before calculating area");

           this.area = 0.0;

       }

   }

   //Own methods

   //1. Method to show the properties of a shape

   public void showProperties(){

       System.out.println();

       System.out.println("The properties of the shape are");

       System.out.println("Shape : " + this.getShape());

       System.out.println("Perimeter : " + this.getPerimeter());

       System.out.println("Area : " + this.getArea());

   

   }

   //2. Method to find and show the difference between the area and perimeter of a shape

   public void getDifference(){

       double diff = this.getArea() - this.getPerimeter();

       System.out.println();

       System.out.println("The difference is " + diff);

   }

}

========= ShapeTest.java  ===========

import java.util.Scanner;

public class ShapeTest {

   public static void main(String [] args){

       Scanner scanner = new Scanner(System.in);

       // create an unknown shape

       Shape shape_unknown = new Shape();

       //get the shape

       System.out.println("The shape is " + shape_unknown.getShape());

       //set the area

       shape_unknown.setArea(scanner);

       //get the area

       System.out.println("The area is " + shape_unknown.getArea());

       //set the perimeter

       shape_unknown.setPerimeter(scanner);

       //get the perimeter

       System.out.println("The perimeter is " + shape_unknown.getPerimeter());

       // create another shape - circle

       Shape shape_circle = new Shape("circle");

       //set the area

       shape_circle.setArea(scanner);

       //get the area

       System.out.println("The area is " + shape_circle.getArea());

       //set the perimeter

       shape_circle.setPerimeter(scanner);

       //get the area

       System.out.println("The perimeter is " + shape_circle.getArea());

       //get the properties

       shape_circle.showProperties();

       //get the difference between area and perimeter

       shape_circle.getDifference();

   }

}

<h2>Sample output:</h2>

The shape is unknown

You must define a shape first before calculating area

The area is 0.0

You must define a shape first before calculating perimeter

The perimeter is 0.0

Enter the radius of the circle

>> 12

The area is 452.448

Enter the radius of the circle

>> 12

The perimeter is 452.448

The properties of the shape are

Shape : circle

Perimeter : 75.408

Area : 452.448

The difference is 377.03999999999996

<h2>Explanation:</h2>

The code above is written in Java. It contains comments explaining important parts of the code. Please go through the code for more explanations. For better formatting, the sample output together with the code files have also been attached to this response.

Download java
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
57aa40cd91dceaa5454e65fc5d209315.png
5 0
3 years ago
The ________ contains the central electronic components of the computer. select one:
Sati [7]
The motherboard contains the central electronic components of the computer.
6 0
3 years ago
He ____ is the section of a cpu core that performs arithmetic involving integers and logical operations.
Gelneren [198K]
Arithmetic/logic Unit (ALU)
3 0
3 years ago
Which unit of the computer works of the output?​
Mrac [35]

Answer:

monitor

Explanation:

this is because monitor displays information so it an output

3 0
3 years ago
Pseudocode of creating a program to convert to IEEE 754 to a real number
Eduardwww [97]

Answer:

  • Step1: Check If the number is Positive or Negative.  
  • Step2: If it is positive then save the sign of it as 0.  
  • Step3: If it is negative then save the sign of it as 1.
  • Step4: Covert the negative number to Positive.
  • Step5: Convert the IEEE 754 to Binary.
  • Step6: convert the integer part into binary form  
  • Step7: Convert fractional part into binary form
  • Step8: To convert Integer part, Devide the number by 2 and note down the reminder and Keep deviding unless dividend is less than 2
  • Step9: copy all the reminders together
  • Step10: Multiply decimal part by 2 unless fractional part is 0.
  • Step11: By noting down integral part, keep multiplying decimal part by new value of 2 untill perfect number is reached.
  • Step6: Find the Mantissa.
  • Step7: Concatinate the Sign, exponent and the mantissa.

Explanation:

For Example : 20.75

First step (converting 50 (in base 10) to binary):

  • No is Positive
  • By dividing 20 by 2, which gives 10 with no remainder 0.
  • Now Devide 10 by 2, which gives 5 with a remainder of 0.
  • Now Devide 5 by 2, which gives 2 the reminder as 1
  • Now Devide 2 by 2, which gives 1 with reminder as 0
  • Now devide 1 by 2, which gives 0 with reminder as 1
  • We read the result from bottom to top  which is 10100

Second part is to convert 0.75 to binary:

  • We have to multiply 0.75 by 2, which gives 1.5. We keep only the integer part, which is 1.  
  • Now, we do 1.5 - 1, which gives 0.5. Now, We multiply 0.5 by 2, which gives 1.  
  • Now we do 1 - 1, which gives 0.
  • Reading from Top to bottom will give 110

Final Answer is : 10100.110

8 0
3 years ago
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