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4 years ago

How does the kinetic energy of particles vary with temperature

1 answer:

6 0

When the average kinetic energy of the molecules go up ( a rise in temperature) the average speed of the molecules increases, the molecules now on average have more kinetic energy .

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A single slit of width 0.3 mm is illuminated by a mercury light of wavelength 254 nm. Find the intensity at an 11° angle to the

MArishka [77]

Answer:

The the intensity at an 11° angle to the axis in terms of the intensity of the central maximum is

$I_c = \frac{I}{I_o} =8.48 *10^{-8}$

Explanation:

From the question we are told that

The width of the slit is $D = 0.3 \ mm = 0.3 *10^{-3} \ m$

The wavelength is $\lambda = 254 \ nm = 254 *10^{-9} \ m$

The angle is $\theta = 11^o$

The intensity of at $11^o$ to the axis in terms of the intensity of the central maximum. is mathematically represented as

$I_c = \frac{I}{I_o} = [ \frac{sin \beta }{\beta }] ^2$

Where $\beta$ is mathematically represented as

$\beta = \frac{D sin (\theta ) * \pi}{\lambda }$

substituting values

$\beta = \frac{0.3 *10^{-3} sin (11 ) * 3.142}{254 *10^{-9} }$

$\beta = 708.1 \ rad$

$I_c = \frac{I}{I_o} = [ \frac{sin (708.1) }{(708.1)}] ^2$

$I_c = \frac{I}{I_o} =8.48 *10^{-8}$

6 0

4 years ago

the 200 g baseball has a horizontal velocity of 30 m/s when it is struck by the bat, B, weighing 900 g, moving at 47 m/s. during

Ivanshal [37]

Solution :

Given :

Mass of the baseball, m = 200 g

Velocity of the baseball, u = -30 m/s

Mass of the baseball after struck by the bat, M = 900 g

Velocity of the baseball after struck by the bat, v = 47 m/s

According to the conservation of momentum,

$Mv+mu=Mv_1+mv_2$

(900 x 47) + (200 x -30) = (900 x $v_1$ ) + (200 x $v_2$ )

36300 = (900 x $v_1$ ) + (200 x $v_2$ )

$9v_1 + 2v_2 = 363$ ..............(i)

$9v_1 = 363 - 2v_2$

$v_1=\frac{363 - 2v_2}{9}$

The mathematical expression for the conservation of kinetic energy is

$\frac{1}{2}Mv^2+\frac{1}{2}mu^2 = \frac{1}{2}Mv_1^2+\frac{1}{2}mv_2^2$

$\frac{1}{2}(900)(47)^2+\frac{1}{2}(200)(-30)^2 = \frac{1}{2}(900)v_1^2+\frac{1}{2}(200)v_2^2$ ................(ii)

$(9)(14)^2+(2)(-30)^2 = (9)v_1^2+2v_2^2$

$21681 = 9v_1^2+2v_2^2$

Substituting (i) in (ii)

$21681= 9\left( \frac{363-2v_2}{9}\right)^2+2v_2^2$

$(363-2v_2)^2+18v_2^2=195129$

$(363)^2+18v_2^2-2(363)(2v_2)+(363)^2-195129=0$

$22v_2^2-145v_2-63360=0$

Solving the equation, we get

$v_2=96 \ m/s, -30 \ m/s$

The negative velocity is neglected.

Therefore, substituting 96 m/s for $v_2$ in (i), we get

$v_1=\frac{363-(2 \times 96)}{9}$

= 19

Thus, only impulse of importance is used to find final velocity.

8 0

3 years ago

According to American Heart Association, your target heart rate is__________.

sladkih [1.3K]

Answer:

Explanation:

A normal heart rate is from 85-95% the other heart rate is not normal because your heart is beating more than normal

4 0

3 years ago

An FM radio wave has a frequency of 7.98E+8 Hz. What is the wavelength of this electromagnetic wave?

Lapatulllka [165]

Answer:

.376 m

Explanation:

c = speed of light = 3 x 10^8 m/s

c = wavelength * freq

3 x 10^8 = 7.98 x 10^8 * f

f = .376 meters

5 0

3 years ago

Which of these statements did you include in your answer? check all that apply the two main parts of an atom are the nucleus and

aleksklad [387]

<u>Both given statements are true.</u> An atom has a nucleus, an electron cloud, and subatomic particles.

There are two main parts of an atom i.e. nucleus (protons + neutrons) and the electron cloud which is composed of three subatomic particles: electrons, protons, and neutrons.

An electron is a subatomic particle having a negative charge on it.

While protons are positively charged particles and are found in the nucleus of an atom due to strong nuclear forces.

On the other hand, a neutron, as the name suggests, is a neutral subatomic particle having no charge at all.

If you need to learn more about subatomic particles click here:

brainly.com/question/16847839

#SPJ4

4 0

1 year ago