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3 years ago

A person should be able to find all the answers to their science questions in the text

Physics

2 answers:

sweet-ann [11.9K]3 years ago

8 0

True is the answer because it’s a Sience book

Vsevolod [243]3 years ago

4 0

TRUE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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A proton moves along the x-axis in the laboratory with velocity uy = 0.6c. An observer moves with a velocity of v=0.8c along the

Dima020 [189]

Explanation:

Given that,

Velocity of the proton in lab frame $u_{x} = 0.6c$

Velocity of the observer v= 0.8c

We need to calculate the velocity of the proton with respect to the observer

Using formula of velocity

$u'=\dfrac{v-u_{x}}{1-\dfrac{u_{x}v}{c^2}}$

$u'=\dfrac{0.8c-0.6c}{1-\dfrac{0.6c\times0.8c}{c^2}}$

$u'=c(\dfrac{0.8-0.6}{1-(0.8\times0.6)})$

$u'=0.385c$

(a). We need to calculate the total energy of the proton in the lab frame

Using formula of kinetic energy

$K.E=m_{0}c^2(\dfrac{1}{\sqrt{1-\dfrac{u_{x}^2}{c^2}}}-1)$

Where, Proton mass energy = m₀c²

Put the value into the formula

$K.E=938.28\times(\dfrac{1}{\sqrt{1-\dfrac{(0.6c)^2}{c^2}}}-1)$

$K.E=938.28\times(\dfrac{1}{\sqrt{1-(0.6)^2}}-1)$

$K.E=234.57\ MeV$

(b). We need to calculate the kinetic energy of the proton in the observer

Using formula of kinetic energy

$K.E=m_{0}c^2(\dfrac{1}{\sqrt{1-\dfrac{u'^2}{c^2}}}-1)$

$K.E=938.28\times(\dfrac{1}{\sqrt{1-\dfrac{(0.385)^2}{c^2}}}-1)$

$K.E=938.28\times(\dfrac{1}{\sqrt{1-(0.385)^2}}-1)$

$K.E=78.366\ MeV$

(c). We need to calculate the momentum of the proton with respect to observer

Using formula of momentum

$P_{obs}=\dfrac{m_{0}u'^2}{\sqrt{1-\dfrac{u'^2}{c^2}}}$

We know that,

Proton mass energy = m₀c²

$m_{0}=\dfrac{938.28}{c^2}$

$P_{obs}=\dfrac{\dfrac{938.28}{c^2}\times(0.385c)^2}{\sqrt{1-\dfrac{(0.385c)^2}{c^2}}}$

$P_{obs}=\dfrac{938.28\times(0.385)^2}{\sqrt{1-0.385^2}}$

$P_{obs}=150.69\ MeV/c$

Hence, This is required solution.

3 0

3 years ago

What<br> are the properties of magnets?

babymother [125]

Answer:

Attractive Property – Magnet

Explanation:

attracts ferromagnetic materials like iron, cobalt, and nickel. Repulsive Properties – Like magnetic poles repel each other and unlike magnetic poles attract each other. Directive Property – A freely suspended magnet always points in a north-south direction.

8 0

3 years ago

A 0.500-kg mass suspended from a spring oscillates with a period of 1.36 s. How much mass must be added to the object to change

lord [1]

The mass that must be added is 0.628 kg

Explanation:

The period of a mass-spring system is given by

$T=2\pi \sqrt{\frac{m}{k}}$

where

m is the mass

k is the spring constant

For the initial mass-spring system in the problem, we have

m = 0.500 kg

T = 1.36 s

Solving for k, we find the spring constant:

$k=(\frac{2\pi}{T})^2 m = (\frac{2\pi}{1.36})^2 (0.500)=10.7 N/m$

In the second part, we want the period of the same system to be

T = 2.04 s

Therefore, the mass on the spring in this case must be

$m=(\frac{T}{2\pi})^2 k =(\frac{2.04}{2\pi})^2 (10.7)=1.128 kg$

Therefore, the mass that must be added is

$\Delta m = 1.128 - 0.500 = 0.628 kg$

Learn more about period:

brainly.com/question/5438962

#LearnwithBrainly

5 0

4 years ago

How many miles will be completed by a runner with a constant speed of 5 mph in 30 minutes?

Mrac [35]

Distance=speed times time
speed=5mph=5 $\frac{mi}{hr}$
time=30mins=30/60hr=1/2hr

so
distance=speed times time
$distance=(5\frac{mi}{hr})(\frac{1}{2}hr)$
$distance=\frac{5mi \space\ hr}{2hr}$
$distance=2.5mi$

he will run 2.5 miles in 30 mins at the speed of 5mph

5 0

3 years ago

when an apple falls towards the earth,the earth moves up to meet the apple.is this true ?if yes,why is the earth's motion not no

stira [4]

Answer:

Yes

Explanation:

Newton's third law

For every action, there is an equal and opposite reaction.

SO if the apple is falling 9.8 m/s2 then the same force is pushing against it.

Hope this helps

6 0

3 years ago