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3 years ago

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The original magnitude of the force on the Q charge was F; what is the magnitude of the force on the Q charge now?

1 answer:

Otrada [13]3 years ago

3 0

Complete Question:

Two small objects each with a net charge of Q (where Q is a positive number) exert a force of magnitude "F" on each other. We

replace one of the objects with another whose net charge is 4Q. The original magnitude of the force on the Q charge was "F"; what is the magnitude of the force on the Q charge now?

Answer:

4 F₀

Explanation:

Assuming that we can treat to both objects as point charges, we can find the force "F" that one charge exerts upon the other applying Coulomb´s law, as follows:

F₀ = K*Q₀² / r₁₂²

If we replace one of the charges by one with a 4Q₀ charge, the new value of F will be as follows:

F₁ = K*Q₀*4Q₀ / r₁₂² =( K*Q₀² / r₁₂²)* 4 = 4* F₀

This value is reasonable, as the electrostatic force is a linear - type one, so it is possible to use the superposition principle (we can get the force exerted by one charge on another without considering the ones due to another charges)

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3 years ago

Read 2 more answers

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ludmilkaskok [199]

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3 years ago

The distance between the centers of the wheels of a motorcycle is 156 cm. The center of mass of the motorcycle, including the ri

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Answer:

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3 years ago