How does gravity affect balanced/unbalanced forces?
2 answers:
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Answer:
The journey started from point A, with a speed of 1 m/s for 10 seconds after which the it became stationary at 10 meters from the start point, for 10 seconds. The journey continued at a higher speed of 2 m/s for 5 seconds and halted (became stationary) again at 20 meters which was the maximum distance reached from the start point
The return journey to the start point started at the 20 meter mark and lasted for 5 seconds, at a speed of 4 m/s
The total distance travelled during the journey from the start point A to the final point B is 40 m
Explanation:
From the start point A to point B, we have;
The speed from A to B = 10 m/(10 s) = 1 m/s
The distance traveled from A to B = 10 m
The time it takes to move from A to B = 10 seconds
From the point B to point C, we have;
The distance traveled from B to C = 0 m, (stationary)
The time it remains at point B distance from the start point = 10 seconds
The speed between point B to C = 0 m/(10 s) = 0 m/s
From the point C to point D, we have;
The distance traveled from C to D = 10 m
The time it takes to move from C to D = 5 seconds
The speed between point C and D = 10 m/(5 s) = 2 m/s
From the point D to point E, we have;
The distance traveled from D to E = 0 m, (stationary)
The time it remains at point D distance from the start point = 10 seconds
The speed between point D to E = 0 m/(10 s) = 0 m/s
From the point E to point F, we have;
The distance traveled from E to F = 20 m (return journey starts at point E)
The time it takes to move from E to F = 5 seconds
The speed between point E to F = 20 m/(5 s) = 4 m/s (Return journey)
Therefore, the journey started from point A, with a speed of 1 m/s for 10 seconds after which the it became stationary at 10 meters from the start point, for 10 seconds. The journey continued at a higher speed of 2 m/s for 5 seconds and halted (became stationary) again at 20 meters which was the maximum distance reached from the start point
The return journey to the start point started at the 20 meter mark and lasted for 5 seconds, at a speed of 4 m/s
The total distance moved, 'd', to and from the start point with reference to the graph is given as follows;
d = (From A to B) 10 m + (From B to C) 0 m + (From C to D) 10 m + (From D to E) 0 m + (From E to F) 20 m = 40 m
The total distance travelled in the journey is 40 m
The total displacement, = 10 m + 10 m - 20 m = 0 m
Answer:
A ) SOLID SPHERE
Explanation:
Moment of inertia of solid sphere = 2/5 M R²
= M K² , K is called radius of gyration
K = √2/5 R
Moment of inertia of solid cylinder = 1/2 M R²
= M K² , K is called radius of gyration
K = 1 /√2 R
Moment of inertia of solid sphere = M R²
= M K² , K is called radius of gyration
K = R
For rolling on inclined plane , acceleration
a =
Putting the value of K for solid sphere
a for solid sphere
a = g sinθ / ( 1 +2/5)
a = .714 g sinθ
Putting the value of K for solid cylinder
a for solid cylinder
a = g sinθ / ( 1 +1/2)
a = .666 g sinθ
Putting the value of K for hollow pipe
a for hollow pipe
a = g sinθ / ( 1 +1 )
a = . 5 g sinθ
So we see that acceleration a for solid sphere is greatest and a for hollow pipe is the least. Hence solid sphere will reach the bottom earliest and hollow pipe will reach the bottom the latest.