What are the vertical asymptotes of the function f(x) = the quantity of 4 x plus 8, all over x squared plus 3 x minus 4?

1 answer:

5 0

4x+8/x^2+3x-4
Vertical asymptotes are vertical lines which correspond to the zeroes of the denominator of a rational function.

the vertical asymptotes (which tell me where the graph can not go) will be at the values
4x+8/x^2+3x-4

if u solve the denominator x should not eqaul to 0

so x^2+3x-4=0 x=1,x=-4

You might be interested in

I don't really know what to do for this one.

Colt1911 [192]

Let, Price of a shirt = x
Price of a Jeans = y

Equations would be: 4x + 3y = 150
x + 2y = 70
x = 70-2y

Substitute it into first equation,
4(70-2y) + 3y = 150
280 - 8y + 3y = 150
-5y = -130
y = 130/5
y = 26

Substitute it into 2nd equation,
x + 2(26) = 70
x = 70-52
x = 18

So, Cost of a Shirt = $18 & Cost of a Jeans = $26

Hope this helps!

3 0

2 years ago

How many triangles and quadrilaterals altogether can be formed using the vertices of a 7-sided regular polygon?

MAVERICK [17]

Answer: The correct option is

(E) 70.

Step-by-step explanation: We are given to find the number of triangles and quadrilaterals altogether that can be formed using the vertices of a 7-sided regular polygon.

To form a triangle, we need any 3 vertices of the 7-sided regular polygon. So, the number of triangles that can be formed is

$n_t=^7C_3=\dfrac{7!}{3!(7-3)!}=\dfrac{7\times6\times5\times4!}{3\times2\times1\times4!}=35.$