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dimulka [17.4K]
3 years ago
10

What are the vertical asymptotes of the function f(x) = the quantity of 4 x plus 8, all over x squared plus 3 x minus 4?

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
5 0
4x+8/x^2+3x-4 
Vertical asymptotes are vertical lines which correspond to the zeroes of the denominator of a rational function<span>.
</span>
the vertical asymptotes (which tell me where the graph can not<span> go) will be at the values 
</span>4x+8/x^2+3x-4

if u solve the denominator x should not eqaul to 0

so x^2+3x-4=0 x=1,x=-4

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When simplifying 4x^3-10x^2+6x/2x^3+x^2-3x, what are the term(s) that can be cancelled
brilliants [131]

Answer:

x can be cancelled

Step-by-step explanation:

we are given

\frac{4x^3-10x^2+6x}{2x^3+x^2-3x}

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and then we can factor it

4x^3-10x^2+6x=2x(2x^2-5x+3)

4x^3-10x^2+6x=2x(2x+1)(x-3)

now, we can factor denominator

2x^3+x^2-3x=x(2x^2+x-3)

2x^3+x^2-3x=x(x-1)(2x+3)

now, we can replace it

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x can be cancelled

3 0
3 years ago
Your interest is $72, your principal is $600 and the rate is 4%. How much time will you need to pay off the loan?
hram777 [196]

Answer:

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2 years ago
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3 years ago
Read 2 more answers
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