Alright, so the first thing I would do is find the LCM of the dividends, which is 20. So we have 10 15/20 and 6 16/20. You can either leave it there and just carry the one (20 in this case) for 3 19/20.
If you multiply 10 by 20 and add 15, or 6 by 20 and add 16 (which I think is easier) you get 215/20 - 136/20 = 79/20. It can be simplified from here if you teacher wants it in the future.
Answer:
The proportion that can be used to find x is;
(200-x)/x = 7/6
Step-by-step explanation:
Now, we want to find the proportion which can be used to find x.
From the question, we are told that the father skater traveled 7 ft for every 6 ft of the slower skater;
this means that the ratio of their speed is 7:6
Now, when they passed each other , the slower skater has traveled x ft, what this means is that the faster skater will have traveled a distance of (200-x) ft at that moment they passed each other.
Mathematically, since their time is equal i.e the time they used to pass each other, then, the ratio of their distances is same as the ratio of their speeds;
Hence;
(200-x)/x = 7/6 or x/(200-x) = 6/7
Hello :
let :

calculate : x ......x <span>≠ -1
</span>





the inverse function is :

domain of : g is the range of : f
as an interval : ]-∞: 3 <span>[</span>U ]3;+∞[
Answer:
.
(Expand to obtain an equivalent expression for the sphere:
)
Step-by-step explanation:
Apply the Pythagorean Theorem to find the distance between these two endpoints:
.
Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:
.
In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between
and
would be:
.
In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:
.
The equation for a sphere of radius
and center
would be:
.
In this case, the equation would be:
.
Simplify to obtain:
.
Expand the squares and simplify to obtain:
.