What is the unknown number to ( +4)+59+70

PLEASE HELP!!!!!!!!<br> 20 POINTS !!!!!!!!!

Kryger [21]

The first one I'll go with 2nd one ...But I'm dumb so hope that helps

8 0

2 years ago

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Any called luna with a friend called joabe carmo plzzzzzz say a word we are looking 4 u

omeli [17]

Answer:

um

Step-by-step explanation:

ok?

5 0

2 years ago

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What number should be placed in the box to help complete the division calculation?

LenKa [72]

Answer:

25

Step-by-step explanation:

25x14=350

8 0

2 years ago

72÷6374<br><img src="https://tex.z-dn.net/?f=72%20%5Cdiv%206374" id="TexFormula1" title="72 \div 6374" alt="72 \div 6374" align=

Ivan

72 divided by 6374 is equal to 0.0113

Hope it helps :)

6 0

3 years ago

The ammunition storage room has 10 feet between the floor and the ceiling. Each box of ammunition is 10 feet tall. Each crate of

KIM [24]

Answer:

the maximum number of crates that can be stacked between the floor and ceiling

$\frac{height \hspace{0.1cm} of \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of \hspace{0.1cm} each \hspace{0.1cm} crate} = \frac{10 \hspace{0.1cm} feet}{12 \hspace{0.1cm} inches} = \frac{10 \times 12 \hspace{0.1cm} inches }{12 \hspace{0.1cm} inches} = 10 \hspace{0.1cm} crates$

where 1 foot = 12 inches. SO the answer is that a maximum of 10 crates can be stacked from floor to ceiling.

Step-by-step explanation:

i) the maximum number of crates that can be stacked between the floor and ceiling

$\frac{height \hspace{0.1cm} of \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of \hspace{0.1cm} each \hspace{0.1cm} crate} = \frac{10 \hspace{0.1cm} feet}{12 \hspace{0.1cm} inches} = \frac{10 \times 12 \hspace{0.1cm} inches }{12 \hspace{0.1cm} inches} = 10 \hspace{0.1cm} crates$

where 1 foot = 12 inches

3 0

2 years ago