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s344n2d4d5 [400]

3 years ago

12

Please help:) what is the mean height when looking at a histogram? how do i find it?

1 answer:

kari74 [83]3 years ago

5 0

Answer:

For each histogram bar, we start by multiplying the central x-value to the corresponding bar height. Each of these products corresponds to the sum of all values falling within each bar. Summing all products gives us the total sum of all values, and dividing it by the number of observations yields the mean.

Step-by-step explanation:

I hope this helps! :)

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Enter the degree of the polynomial 10x^4+4x^5+7x^2+6x^7-8x^6

seropon [69]

I think the degree would be 7 because it's the largest exponent on the variable

7 0

3 years ago

Solve the equation: x/2-18=(-28)

dedylja [7]

Answer:

x = -20

Step-by-step explanation:

First we can rearrange the equation:

$\frac{x}{2}$ -18 = -28

2 * $\frac{x}{2}$ - 18 = -28 * 2

The 2s canel out

x - 36 = - 56

x = -20

8 0

3 years ago

Please help! Answer choices are <br> 0<br> 2<br> 14<br> 7

wlad13 [49]

Answer:

The answer for the algebraic expression is >> 7

3 0

3 years ago

Read 2 more answers

Mr. Perez ordered 12 new jerseys for the middle school baseball team . Each jersey costs the same amount. He paid \$|O for shipp

Zina [86]

Answer:

each jersey was 15 dollars.

Step-by-step explanation:

190-10= 180

180/12= 15

hope this helps!!

3 0

3 years ago

Read 2 more answers

Are two lines parallel, perpendicular or neither 3x+7y=15 and 7x-3y=6

maw [93]

Answer:

The lines are perpendicular

Step-by-step explanation:

we know that

If two lines are parallel, then their slopes are equal

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

we have

$3x+7y=15$ ----> equation A

isolate the variable y

$7y=-3x+15$

Divide by 7 both sides

$y=-\frac{3}{7}x+\frac{15}{7}$

The slope of the line A is $m_A=-\frac{3}{7}$

$7x-3y=6$ ----> equation B

isolate the variable y

$3y=7x-6$

Divide by 3 both sides

$y=\frac{7}{3}x-2$

The slope of the line B is $m_B=\frac{7}{3}$

Compare the slope of both lines

$m_A=-\frac{3}{7}$

$m_B=\frac{7}{3}$

so

$m_A \neq m_B$ ----> the lines are not parallel

Find the product of the slopes

$-\frac{3}{7}(\frac{7}{3})=-1$ ----> the lines are perpendicular

4 0

3 years ago