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Softa [21]
3 years ago
9

Becky likes to skate at a movie theater that is due south of her school and west of her favorite ice cream parlor. If the movie

theater is 4 miles from her school and the straight-line distance between the school and the I cream parlor is 5 miles, how far is the movie theater from the ice cream parlor
Mathematics
1 answer:
garik1379 [7]3 years ago
8 0

Answer:

The movie theater is 3 miles away from the the ice cream parlor.

Step-by-step explanation:

The position of Becky's school (S) and the movie theater (M)and the ice cream parlor (I) make a right triangle.

Hence, Δ SMI is a right triangle with ∠ M is the right angle i.e. 90°.

Now, given length of segment SM is 4 miles and the hypotenuse i.e. line segment SI = 5 miles.

Hence, applying Pythagoras Theorem,

SI² = SM² + MI²

⇒ 5² = 4² + MI²

⇒ MI = 3 miles.

Therefore, the movie theater is 3 miles away from the ice cream parlor. (Answer)

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Work out the value of 23 - 4b. When b = 3
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Step-by-step explanation:

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Read 2 more answers
A. The lengths of pregnancies in a small rural village are normally distributed with a mean of 266 days and a standard deviation
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Step-by-step explanation:

a.

mean = 266

sd = 14

cumulative probability = 0.01 so the standard score = -2.33 and 2.33 to the right and left

we find X-upper and X-lower

X-lower = 266-2.33*14 = 233.38

X-upper = 266+2.33*14 = 298.62

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we have sample size = 35

X-lower = 266-2.33*14/√35 = 260.49

X-upper = 266+2.33*14/√35 = 271.5

Between 260.49 and 271.5

b. cumulative probaility = 0.25

standard score = 1.96 to the right and left

x-lower = 6.9-1.96x0.9 = 5.14

x-upper = 6.9+1.96x0.9 = 8.66

Between 5.14 and 8.66

if sample size = 45

x-lower = 6.9-1.96*0.9/√45 = 6.64

x-upper = 6.9+1.96*0.9/√45 = 7.2

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x-lower = 265.3-0.67x15.2 = 255.12

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d. we will have critical values at 1.00 and -1.00

X-lower = 265-1x16 = 249

x-upper = 265+1x16 = 281

Between 249 and 281

with sample size = 44

x-lower = 265-1x16/√44 = 262.59

x-upper = 265+1x16/√44 = 267.41

Between 262.59 and 267.41

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