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scoray [572]
3 years ago
6

Solve for M. 2G/k=5/M

Mathematics
1 answer:
BartSMP [9]3 years ago
6 0

5k/2G is the answer to the problem.

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Find the remaining trigonometric functions of θ based on the given information.csc θ = 257 and cos θ < 0
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Cos(<span>θ) < 0, so we know it would be in Quadrant 2 or 3
then csc(</span>θ) = 257, but csc(θ) = \frac{1}{sin(θ)} = 257
==> sin(<span>θ) = \frac{1}{257}
it is positive, so now we can determine that is in Quadrant 2

sin(</span>θ) = opp./hyp both of opp and hyp are positive but adj suppose to negative because that way it leads the cos(<span>θ) < 0
</span>cos(<span>θ) = adj/hyp
</span>Pythereom to find the adj: 257^{2} -  1^{2}  = adj ==\ \textgreater \  adj  \sqrt{ 257^{2} -   1^{2} } ==\ \textgreater \  adj = 16 \sqrt{258}

cosθ = \frac{16 \sqrt{258} }{257} &#10;
tanθ = \frac{1}{16 \sqrt{258} }
cos<span>θ = </span>16 \sqrt{258}
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