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Delicious77 [7]
2 years ago
14

Graph a line with a slope of 1/4 that contains the point (6, 3).

Mathematics
1 answer:
Semenov [28]2 years ago
8 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we know that

The equation of a line in point slope form is

y-y1=m(x-x1)

we have

(x_1,y_1)=(6,3)

m=\frac{1}{4}

substitute

y-3=\frac{1}{4}(x-6)

The easiest way to graph a line is to calculate the intercepts

The<u><em> x-intercept </em></u>is the value of x when the value of y is equal to zero

For y=0

0-3=\frac{1}{4}(x-6)

-12=(x-6)

x=-12+6=-6

The x-intercept is the point (-6,0)

The <u><em>y-intercept</em></u> is the value of y when the value of x is equal to zero

For x=0

y-3=\frac{1}{4}(0-6)

y-3=-\frac{3}{2}

y=-\frac{3}{2}+3

y=1.5

The y-intercept is the point (0,1.5)

Plot the intercepts and join the points to graph the line

(-6,0) and (0,1.5)

The graph in the attached figure

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