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Sergio [31]
3 years ago
12

Find the area of the irregular figure. I've been stuck on this for awhile. Please help and explain how you did it.

Mathematics
2 answers:
Reptile [31]3 years ago
7 0

to the risk of sounding redundant, as the previous posting is absolutely correct.

Check the picture below.

we know the circum-inscribing figure is a square, namely a 23x20, so it has an area of 23*20 = 460 ft².

the distance from the bottom up, is 20, however to the tip of the triangle is 12, so the diffference is 20 - 12 = 8, meaning the triangle, in yellow, has a height/altitude of 8 ft, and we know its base is 23 ft.

so if we simply take the whole area of the square, and then subtract the area of the triangle, we're in effect making a whole in the squarish area, and what's leftover is the shaded area.

\bf \stackrel{\textit{square's area}}{(23\cdot 20)}~~~~-~~~~\stackrel{\textit{triangle's area}}{\cfrac{1}{2}(23)(8)}\implies 460~~-~~92\implies 368~ft^2

IrinaVladis [17]3 years ago
6 0

Answer: 368 ft^2

Step-by-step explanation:

Pretend it is a square and multiply both sides (23*20=460). The triangle that is cut out has an area of 92 (23*8/2). We know the height of the triangle is 8 because 20-12. We subtract 460-92 and get our answer. :)

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Divid 15 into two parts such that the sum of their reciprocal is 3/10
Klio2033 [76]
From the information obtained from the question, two equations can be created:
 
Let x and z be the two numbers (parts)

\frac{1}{z}   +   \frac{1}{x}  =   \frac{3}{10} .  .  .  . (1)

z  +   x  =  15  .  .  .  . (2)

By transposing (2), make 'z' the subject of the equation
z = 15 - x  .  .  .  . (3)

By substituting (3) into equation (1) to find a value for x
\frac{1}{(15 - x)} + \frac{1}{x} = \frac{3}{10}

\frac{15}{( 15 - x ) ( x )}  =   \frac{3}{10}

3 ( - x^{2}  + 15 x )  =  150

3 x^{2}  - 45x + 150 = 0

⇒  ( x - 5 )  ( x - 10 )  = 0

∴ either ( x - 5) = 0        OR    ( x - 10 ) = 0

Thus x = 5 or x = 10

By substituting the values of x into (2) to find z

     z + (5) = 15       OR      z + (10) = 15

    ⇒      z = 10      OR                 z = 5

So, the two numbers or two parts into which fifteen is divided to yield the desired results are 5 and 10.





5 0
3 years ago
If the temperature in degrees Celsius , of a particular place from January to December was given as 9,11,12,12,13,14,14,14,16,15
Ira Lisetskai [31]

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use a calculator

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5 0
3 years ago
A house that you are interested in has the following facts listed online: Price = $214,000 APR = 1.15% Down Payment must be 9.5%
gizmo_the_mogwai [7]

9514 1404 393

Answer:

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Step-by-step explanation:

a) The down payment is 9.5% of the price, so is ...

  down = 0.095×$214,000 = $20,330

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b) The amount of the loan is the remaining value after the down payment is made:

  $214,000 -20,330 = $193,670

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c) The monthly payment is given by the amortization formula:

  A = P(r/12)/(1 -(1 +r/12)^(-12t))

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6 0
3 years ago
Please help, i'm horrible @ math :)
katovenus [111]
   
\displaystyle\\
1 \frac{2}{5} +\Big(-5 \frac{1}{2} \Big) = ? \\  \\ 
1 \frac{2}{5} = \frac{1\times 5+2}{5}=\boxed{\frac{7}{5}} \\  \\ 
-5 \frac{1}{2} =-5 -\frac{1}{2} = \frac{-5\times2-1}{2} =\frac{-10-1}{2}=\frac{-11}{2}= \boxed{-\frac{11}{2} }\\  \\ \texttt{OR} \\  \\ 
-5 \frac{1}{2} = -\Big(5 \frac{1}{2} \Big)= -\Big( \frac{5\times2+1}{2} \Big)=-\Big( \frac{11}{2} \Big)= \boxed{-\frac{11}{2} }


\displaystyle\\
\Longrightarrow ~~1 \frac{2}{5} +\Big(-5 \frac{1}{2} \Big) =\frac{7}{5} -\frac{11}{2} = \frac{7\times 2}{5\times 2} -\frac{11\times 5}{2\times 5} = \\  \\ 
= \frac{14}{10} -\frac{55}{10} = \frac{14-55}{10} =\frac{-41}{10} = -\frac{41}{10}=-\frac{40+1}{10}=\boxed{\boxed{-4\frac{1}{10}}}



7 0
3 years ago
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