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Karolina [17]
3 years ago
5

Ms. tucker travels through two intersections with traffic lights as she drives to the market. the traffic lights operate indepen

dently. the probability that both lights will be red when she reaches them is 0.22. the probability that the first light will be red and the second light will not be red is 0.33. what is the probability that the second light will be red when she reaches it?
Mathematics
1 answer:
sergij07 [2.7K]3 years ago
4 0
The probability of two independent events occurring one after the another is the product of these probabilities, i.e. P(red1,red2)=0.22

We have given that the probability of the first being red and the second not being red is 0.33,

The probability of the first light being red is P(red1)=0.33+0.22=0.55. 

And we know that these events are independent, then 

P(red1)*P(red2)=P(red1,red2)
0.55*P(red2)=0.22
P(red2)=0.4
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Answer:

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Step-by-step explanation:

Let us assume the number of trees in each row  = m

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Now, Total number of Trees = Number of Rows x Number of trees in 1 row

⇒ 651  = m (m + 10)

651 = m^2 + 10m\\\implies  m^2 + 10m - 651 =0\\or,   m^2 + 31m  21m - 651 =0\\or, m(m +31) -21(m+31) =0\\\implies (m +31) (m-21) = 0

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⇒ m= -31, or m = 21

Now, as m = The number of trees in each row, so m ≠ -31

So, m =  21

Hence, the number of trees in each row is m = 21.

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