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lorasvet [3.4K]
4 years ago
6

Use the function below to find f(4). F(x) = 3x

Mathematics
2 answers:
Sonja [21]4 years ago
5 0
Since F(X) = 3^X,

F(4) = 3^4 = 81
mamaluj [8]4 years ago
3 0

Answer:81

Step-by-step explanation:

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The answer of your question is x - 4 y=8
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-2.074 + 1.8 I need help it’s math and it’s multiplying decimals
jok3333 [9.3K]

Answer:

-0.274

Step-by-step explanation:

You could just use the calculator, BUT if you want to use pencil paper you have to align them decimal over decimal:

 -2.074

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3 0
3 years ago
Which dot plot matches the tally chart below?
zubka84 [21]

Answer:

(A) my friend

Step-by-step explanation:

please mark Brainliest because the other answer above me is wrong

5 0
3 years ago
Read 2 more answers
Help me! Will give 18 Points and will mark a person as brainiest to the first person who answers!
Reika [66]

Answer:

-201.1

-200.9

-200

201

201.8

Step-by-step explanation:

For the given statement we have come to know that number in the line who have negative vales are less than the positive value

so in the number line we can see that

-201.1 is negative value in the number line and it has least value so

next value is -200.9 who is also negative and least but greater than -201.1

moving towards next we can see the value of 200 who is also negative but greater than from -200.9 so moving towards next

we can see that 201.8 is positive value so it is greater from all the past values

next the value 201 is greater than 200

so after these explanation you can see that numbers moving from negative to positive values and its show greatest values as well

hope it will be brainliest to you .

thank you

4 0
4 years ago
Working for a car company, you have been assigned to find the average miles per gallon (mpg) for acertain model of car. you take
Orlov [11]

Answer:

a) The 95% confidence interval for the mean mpg, for the certain model of car is (23.3, 30.1). This means that we are 95% sure that the true mean mpg of the model of the car is between 23.3 mpg and 30.1 mpg.

b) Increasing the confidence level, the value of T would increase, thus increasing the margin of error and making the interval wider.

c) 37 cars would have to be sampled.

Step-by-step explanation:

Question a:

We have the sample standard deviation, and thus, the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 15 - 1 = 14

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 14 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.1448

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.1448\frac{6.2}{\sqrt{15}} = 3.4

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 26.7 - 3.4 = 23.3 mpg.

The upper end of the interval is the sample mean added to M. So it is 26.7 + 3.4 = 30.1 mpg.

The 95% confidence interval for the mean mpg, for the certain model of car is (23.3, 30.1). This means that we are 95% sure that the true mean mpg of the model of the car is between 23.3 mpg and 30.1 mpg.

b. What would happen to the interval if you increased the confidence level from 95% to 99%? Explain

Increasing the confidence level, the value of T would increase, thus increasing the margin of error and making the interval wider.

c. The lead engineer is not happy with the interval you constructed and would like to keep the width of the whole interval to be less than 4 mpg wide. How many cars would you have to sample to create the interval the engineer is requesting?

Width is twice the margin of error, so a margin of error of 2 would be need. To solve this, we have to consider the population standard deviation as \sigma = 6.2, and then use the z-distribution.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How many cars would you have to sample to create the interval the engineer is requesting?

This is n for which M = 2. So

M = z\frac{\sigma}{\sqrt{n}}

2 = 1.96\frac{6.2}{\sqrt{n}}

2\sqrt{n} = 1.96*6.2

\sqrt{n} = \frac{1.96*6.2}{2}

(\sqrt{n})^2 = (\frac{1.96*6.2}{2})^2

n = 36.9

Rounding up:

37 cars would have to be sampled.

8 0
3 years ago
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