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adelina 88 [10]
3 years ago
14

WHAT IS THE DOMAIN OF f(x)=4^x

Mathematics
2 answers:
11111nata11111 [884]3 years ago
7 0
It is C , All real numbers !
True [87]3 years ago
5 0
C. "All real numbers"

because x can be anything, there are no restrictions.
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Please Please Please help
MakcuM [25]

Answer:

6,6

Step-by-step explanation:

a

6 0
3 years ago
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RADIATION ON MARS
Darina [25.2K]

Answer:

0.71% probability that the daily average amount of radiation received by a rover will exceed 102

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 100, \sigma = 20, n = 600, s = \frac{20}{\sqrt{600}} = 0.8165

What is the probability that the daily average amount of radiation received by a rover will exceed 102?

This is 1 subtracted by the pvalue of Z when X = 102. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{102 - 100}{0.8165}

Z = 2.45

Z = 2.45 has a pvalue of 0.9929

1 - 0.9929 = 0.0071

0.71% probability that the daily average amount of radiation received by a rover will exceed 102

5 0
3 years ago
*PLEASE HELP WILL GIVE BRAINLIEST*
Likurg_2 [28]
The second one i think 
7 0
3 years ago
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What is the interquartile range of this data set. 4,5,7,9,10,14,16,24
ehidna [41]

Answer:

The interquartile range is 10.

Step-by-step explanation:

(xu-xl)=10

5 0
4 years ago
Please find out what y=mx+c picture is attached above pls help!
mel-nik [20]
First of all, your sample equation is wrong, it is y=mx+b, not y=mx+c, but anyway, the finished equation is going to be y=3, hope this helps
3 0
3 years ago
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