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2 years ago

WHAT IS THE DOMAIN OF f(x)=4^x

Mathematics

2 answers:

11111nata11111 [884]2 years ago

7 0

It is C , All real numbers !

True [87]2 years ago

5 0

C. "All real numbers"

because x can be anything, there are no restrictions.

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Which pairs of rational numbers are equivalent? Select all that apply.

ser-zykov [4K]

-0.5 is equivalent to - 1/2

8 0

3 years ago

Read 2 more answers

Can someone please help me with part b?

gogolik [260]

Answer:

x-intercept(s): (-2, 0), (6, 0)

y-intercept(s): (0, -6)

Step-by-step explanation:

An x-intercept represents the point(s) at which the parabola intersects the x axis. A parabola can have 0, 1, or 2 x-intercepts.

A y-intercept represents the point at which the parabola intersects the y axis. A parabola always has exactly 1 y-intercept.

Hope it helps :) and let me know if you're still confused.

8 0

1 year ago

For about $1 billion in new space shuttle expenditures, NASA has proposed to install new heat pumps, power heads, heat exchanger

11111nata11111 [884]

Answer:

The probability of one or more catastrophes in:

(1) Two mission is 0.0166.

(2) Five mission is 0.0410.

(3) Ten mission is 0.0803.

(4) Fifty mission is 0.3419.

Step-by-step explanation:

Let X = number of catastrophes in the missions.

The probability of a catastrophe in a mission is, P (X) = $p=\frac{1}{120}$ .

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}\frac{1}{120}^{x}(1-\frac{1}{120})^{n-x};\x=0,1,2,3...$

In this case we need to compute the probability of 1 or more than 1 catastrophes in n missions.

Then the value of P (X ≥ 1) is:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-{n\choose 0}\frac{1}{120}^{0}(1-\frac{1}{120})^{n-0}\\=1-(1\times1\times(1-\frac{1}{120})^{n-0})\\=1-(1-\frac{1}{120})^{n-0}$

(1)

Compute the compute the probability of 1 or more than 1 catastrophes in 2 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{2-0}=1-0.9834=0.0166$

(2)

Compute the compute the probability of 1 or more than 1 catastrophes in 5 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{5-0}=1-0.9590=0.0410$

(3)

Compute the compute the probability of 1 or more than 1 catastrophes in 10 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{10-0}=1-0.9197=0.0803$

(4)

Compute the compute the probability of 1 or more than 1 catastrophes in 50 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{50-0}=1-0.6581=0.3419$

6 0

3 years ago

You select a card at random from the cards that make up the word replacement without replacing the card,you choose a second card

serious [3.7K]

Answer:

34/55

Step-by-step explanation:

Find the probability of the opposite; not a single vowel chosen.

So, the consonants are 7, so 7/11 times 6/10, which is 21/55.

Then, just 1 - 21/55 to get 34/55

6 0

3 years ago

Please help. Find the value of x

enot [183]

21x is 21x im glad that I can help you

8 0

3 years ago