1: establish the angles, basically label one x (the small one) and the other y (the bigger one)
2. supplementary angles add up to 180, so therefore you have the equation x + y = 180.
3. so y (the bigger one) is 8 less than 3 times the smaller one (x) therefore you come up with the equation y = 3x - 8
4. plug in the equation of the bigger one into the other equation
x + 3x - 8 = 180
(combine like terms)
4x - 8 = 180
5. solve the equation by adding 8 to 180, then by dividing by 4.
x should equal 47
6. plug in 47 into the x + y = 180 equation, subtract 47 from 180 and you end up with 133
i hope i explained it alright
This question not incomplete
Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
Hope this helps :)
Step-by-step explanation:
Answer:75
Step-by-step explanation:
90-15=75
Answer:
(a) Speed = 6.875 m/s
(b) Kinetic Energy = 1.70 kJ
(c) Average power = 1.06 kW
Step-by-step explanation:
Given:
d = 5.5 m
t = 1.6 s
W = 706 N
Part (a)
Using the equation of motion with the assumption of zero initial speed:


The speed of the sprinter then become:

Part (b)
Convert the weight of the sprinter to mass:



KE (Kinetic Energy) can then be calculated as:



Part (c)
The change of the kinetic energy is equivalent to the work done by the sprinter. The average power P is the rate of the work done and can be calculated as


