Question

Area of a rectangle is 2c^3-c^2+6 square units. If the length of the field is c-2 units, what is its width

Answer 1

Area of rectangle= length * width

Area of rectangle= $2c^{3}-c^{2}+6$=(c-2)* width

To, get the width, let us divide by (c-2) on both sides

$\frac{2c^{3}-c^{2}+6 }{c-2}$=$\frac{c-2}{c-2} * width$

Width= $\frac{2c^{3}-c^{2}+6}{c-2}$