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siniylev [52]
3 years ago
8

Evaluate f(x) = 2x4 - 4x3-11x2+3x-6 for x=-2 f (-2) =?

Mathematics
2 answers:
ollegr [7]3 years ago
8 0

Answer:

f(- 2) = 8

Step-by-step explanation:

Evaluating for x = - 2

f(- 2) = 2(-2)^{4} - 4(- 2)³ - 11(- 2)² + 3(- 2) - 6

       = (2 × 16) + (- 4 × - 8) + (- 11 × 4) - 6 - 6

       = 32 + 32 - 44 - 6 - 6 = 8


marusya05 [52]3 years ago
5 0

Answer:

8

Step-by-step explanation:

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Answer:

Option A

Step-by-step explanation:

22+(-32) is the same thing as 22-32.

22-32=-10

<h3>Let's see if the given options are equal:</h3>

Option A:

22+(-22)+(-10) \\22-22-10\leftarrow \text{Distribute -1 into the Parentheses.} \\0-10\\\boxed {-10}

Option A's expression has the same value as the expression given.

Option B:

22+(22)+(-10)

22+22-10\\44-10\\\boxed {34}

Option B's expression does not have the same value as the expression given.

Option C:

22+(-22)+(10)\\22-22+10\\0+10\\\boxed {10}

Option C's expression does not have the same value as the expression given.

Option D:

22+0+32\\22+32\\\boxed{54}

Option D's expression does not have the same value as the expression given.

<h3>The correct answer should be A: 22+(-22)+(-10).</h3>
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Ramona went to a theme park during spring break. She was there for 8 hours and rode 24 rides. At what rate did Ramona ride rides
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3 years ago
In in the previous activity you solved a system of equations representing the carnival admissions using the elimination method i
Mariulka [41]

Answer:

The value of a=300 and value of k=200

If you solve the above system of equations by elimination method, you will get the same values of a and k.

In Equation 1 k+a=500 both variables k has 1 as their coefficient.

Step-by-step explanation:

We need to solve the system of equations using substitution method

The equation are:

k + a = 500--eq(1)\\3k + 10a = 3,600 --eq(2)

For substitution method, we find value of k from equation 1 and put in equation 2

From \ eq(1) \ we \ get\\k=500-a

Putting it in eq(2)

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So, we get value of a = 300

Now finding value of k by putting value of a in equation k=500-a

k=500-a\\Putting \ a \ =500\\k=500-300\\k=200

So, we get value of k =200

The value of a=300 and value of k=200

If you solve the above system of equations by elimination method, you will get the same values of a and k.

In Equation 1 k+a=500 both variables k has 1 as their coefficient.

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