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PSYCHO15rus [73]
2 years ago
13

The employees of a firm that manufactures insulation are being tested for indications of asbestos in their lungs. The firm is re

quested to send three employees who have positive indications of asbestos to a medical center for further testing. If 30% of the employees have positive indications of asbestos in their lungs, find the probability that eleven employees must be tested in order to find three positives. (Round your answer to three decimal places.)
Mathematics
1 answer:
diamong [38]2 years ago
8 0

Answer:

0.070

Step-by-step explanation:

Y = number on trial

Y has a negative binomial distribution

r = 3

P = 30% = 0.3 probability of positive indication.

P(Y = 11) probability of 11 employees that must be tested to get 3 positives

Y-1Cr-1*p^r*q^(y-r)

Y-1 = 11-1 = 10

r-1 = 3 -1 = 2

10C2 x 0.3³x0.7⁸

45x0.027x0.05764801

= 0.070

This is the probability that 11 employees must be tested to get 3 positives.

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Answer:

The two solutions are 5 and 3

Step-by-step explanation:

The equation of the absolute has two solutions because IxI = a means x = a and x = -a

Let us solve the question using this fact

∵ I2x - 8I + 3 = 5

→ Subtract 3 from both sides

∴ I2x - 8I + 3 - 5 = 5 - 3

∴ I2x - 8I = 2

By using the fact above

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∵ 2x - 8 = 2

→ Add 8 to both sides

∴ 2x - 8 + 8 = 2 + 8

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→ Divide both sides by 2 to find x

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→ 2nd solution

∵ 2x - 8 = -2

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∴ 2x - 8 + 8 = -2 + 8

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∴ The two solutions are 5 and 3

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3 years ago
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That means for the equation to be true y has to be 12.

Hope this helps!
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